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Stels [109]
4 years ago
8

Please help thank you.

Mathematics
1 answer:
Alik [6]4 years ago
7 0
Hello!

If By = 52 then m<BAY = 26

m<BAC = 90

m<BAC = m<BAY + m<YAC

Substitute the values we know

90 = 26 + m<YAC

Subtract 26 from both sides

64 = m<YAC

The answer is B

Hope this helps!
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Write the slope intersect form of the equation. <br><br> Through (8,1) perpendicular to y =1/2x +2
dolphi86 [110]

Answer:

Step-by-step explanation:

y= -(1/2)x - 5

6 0
2 years ago
Let Y1 and Y2 have the joint probability density function given by:
Ann [662]

Answer:

a) k=6

b) P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

Step-by-step explanation:

a) if

f (y1, y2) = k(1 − y2), 0 ≤ y1 ≤ y2 ≤ 1,  0, elsewhere

for f to be a probability density function , has to comply with the requirement that the sum of the probability of all the posible states is 1 , then

P(all possible values) = ∫∫f (y1, y2) dy1*dy2 = 1

then integrated between

y1 ≤ y2 ≤ 1 and 0 ≤ y1 ≤ 1

∫∫f (y1, y2) dy1*dy2 =  ∫∫k(1 − y2) dy1*dy2 = k  ∫ [(1-1²/2)- (y1-y1²/2)] dy1 = k  ∫ (1/2-y1+y1²/2) dy1) = k[ (1/2* 1 - 1²/2 +1/2*1³/3)-  (1/2* 0 - 0²/2 +1/2*0³/3)] = k*(1/6)

then

k/6 = 1 → k=6

b)

P(Y1 ≤ 3/4, Y2 ≥ 1/2) = P (0 ≤Y1 ≤ 3/4, 1/2 ≤Y2 ≤ 1) = p

then

p = ∫∫f (y1, y2) dy1*dy2 = 6*∫∫(1 − y2) dy1*dy2 = 6*∫(1 − y2) *dy2 ∫dy1 =

6*[(1-1²/2)-((1/2) - (1/2)²/2)]*[3/4-0] = 6*(1/8)*(3/4)=  9/16

therefore

P(Y1 ≤ 3/4, Y2 ≥ 1/2) =  9/16

8 0
3 years ago
The A&amp;M Hobby Shop carries a line of radio-controlled model racing cars. Demand for the cars is assumed to be constant at a
Bond [772]

Answer:

Step-by-step explanation:

A) Demand per month= 40 cars

Annual Demand (D)= 12*40 = 480

Fixed Cost per order (K)= 15

Holding Cost= 20% of cost= 60 *0.2 = 12

a. Economic Order Quantity=

Q^{*}={\sqrt {{\frac {2DK}{h}}}}

= √(2*480*15)/12

=34.64 ~ 35

Total Cost =P*D+K(D/EOQ)+h(EOQ/2) P= Cost per unit

= 60*480+ 15(480/35) + 12(35/2)

= 28800+ 205.71+ 210

=$29215.71

B). Backorder Cost (b)= $45

Qbo= Q* × √( b+h/ h)

= 35*√(12+45/ 45)

= 35* 1.12

=39.28 ~ 39

Shortage (S)= Qbo * (K/K+b)

= 39* (15/15+45)

= 39* 0.25

= 9.75

Total Cost Minimum=( bS2/ 2Qbo) + P (Qbo- S)2/2Qbo + K(D/Qbo)

=45* 9.752 / 2* 392 + 60 (39-9.75)2/ 2* 392 + 15 ( 480/39)

= 1.40+ 21.9.+ 184.61

=$207.91

C)Length of backorder days (d) = Demand ÷ amount of working days

d = 480 ÷ 300

d = 1.6

Calculate the backorders as the maximum number of backorders divided by the demand per day

s/d = 9.75/1.6 = 6.09 days (answer)

D) Calculate the difference in total between not using backorder:

$207.85 + $207.85 - 207.91 = $207.79

The saving in using backorder is $207.79.

Therefore I would recommend using a backorder

6 0
3 years ago
HELP! WILL GIVE BRAINLEST
trasher [3.6K]

Answer:

Option C: 41

Step-by-step explanation:

<ABD+<CBD=90

<ABD=8x+1

<CBD=6x+5

(8x+1)+(6x+5)=90

Combine like terms

(8x+6x)+(1+5)=90

14x+6=90

14x=90-6

14x=84

divide both sides by 14

x=6

Now we plug that value into <DBC = 6x+5

6(6)+5=

36+5

41

7 0
2 years ago
Read 2 more answers
Can yall help me with this?<br> Thank you!
Ray Of Light [21]

Answer:

<u>1260 degrees (1260°)</u>

Step-by-step explanation:

<u>Formula to Find Sum of Interior Angles of a Polygon</u>

  • 180 (n - 2)
  • n is the <u>number of sides</u> of the polygon

<u>Nonagon (9-sided polygon)</u>

  • 180 (9 - 2)
  • 180 × 7
  • <u>1260 degrees (1260°)</u>
4 0
3 years ago
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