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nexus9112 [7]
3 years ago
6

Need help assoon as possible please

Mathematics
1 answer:
satela [25.4K]3 years ago
4 0
It would be the last one because uvw is congruent to xvy

hope it helps :)
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Can the measures 6cm 15cm 6cm make a triangle
trapecia [35]

Answer:

Yes!

Step-by-step explanation:

Hi there! I'm glad I was able to help you answer this question!

You indeed can make a triangle with the given lengths, but it isn't going to be a perfect triangle, since one of the lengths is longer than the other two.

Also keep in mind that we are only given THREE lengths, and the prefix "tri" in triangle means three (sides). :)

I hope this helped you! If you have any other questions, leave a comment below!

7 0
3 years ago
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MATH - look at the picture and i will mark you as brainliset if you answer correctly.
mote1985 [20]

Answer:

C is the answer

Step-by-step explanation:

It's very obvi lol

3 0
3 years ago
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What are the zeros of the function g(x) = (x + 6) (x – 4)(x + 2) ?
vitfil [10]

9514 1404 393

Answer:

  x in {-6, -2, 4}

Step-by-step explanation:

The zero product rule tells you that a product will be zero if and only if one of the factors is zero. These binomial factors are zero when x has a value that is opposite the constant of the binomial.

  x +6 = 0   ⇒   x = -6

  x -4 = 0   ⇒   x = 4

  x +2 = 0   ⇒   x = -2

The zeros of the function are the x-values -6, -2, and 4.

5 0
3 years ago
Let X denote the length of human pregnancies from conception to birth, where X has a normal distribution with mean of 264 days a
Kaylis [27]

Answer:

Step-by-step explanation:

Hello!

X: length of human pregnancies from conception to birth.

X~N(μ;σ²)

μ= 264 day

σ= 16 day

If the variable of interest has a normal distribution, it's the sample mean, that it is also a variable on its own, has a normal distribution with parameters:

X[bar] ~N(μ;σ²/n)

When calculating a probability of a value of "X" happening it corresponds to use the standard normal: Z= (X[bar]-μ)/σ

When calculating the probability of the sample mean taking a given value, the variance is divided by the sample size. The standard normal distribution to use is Z= (X[bar]-μ)/(σ/√n)

a. You need to calculate the probability that the sample mean will be less than 260 for a random sample of 15 women.

P(X[bar]<260)= P(Z<(260-264)/(16/√15))= P(Z<-0.97)= 0.16602

b. P(X[bar]>b)= 0.05

You need to find the value of X[bar] that has above it 5% of the distribution and 95% below.

P(X[bar]≤b)= 0.95

P(Z≤(b-μ)/(σ/√n))= 0.95

The value of Z that accumulates 0.95 of probability is Z= 1.648

Now we reverse the standardization to reach the value of pregnancy length:

1.648= (b-264)/(16/√15)

1.648*(16/√15)= b-264

b= [1.648*(16/√15)]+264

b= 270.81 days

c. Now the sample taken is of 7 women and you need to calculate the probability of the sample mean of the length of pregnancy lies between 1800 and 1900 days.

Symbolically:

P(1800≤X[bar]≤1900) = P(X[bar]≤1900) - P(X[bar]≤1800)

P(Z≤(1900-264)/(16/√7)) - P(Z≤(1800-264)/(16/√7))

P(Z≤270.53) - P(Z≤253.99)= 1 - 1 = 0

d. P(X[bar]>270)= 0.1151

P(Z>(270-264)/(16/√n))= 0.1151

P(Z≤(270-264)/(16/√n))= 1 - 0.1151

P(Z≤6/(16/√n))= 0.8849

With the information of the cumulated probability you can reach the value of Z and clear the sample size needed:

P(Z≤1.200)= 0.8849

Z= \frac{X[bar]-Mu}{Sigma/\sqrt{n} }

Z*(Sigma/\sqrt{n} )= (X[bar]-Mu)

(Sigma/\sqrt{n} )= \frac{(X[bar]-Mu)}{Z}

Sigma= \frac{(X[bar]-Mu)}{Z}*\sqrt{n}

Sigma*(\frac{Z}{(X[bar]-Mu)})= \sqrt{n}

n = (Sigma*(\frac{Z}{(X[bar]-Mu)}))^2

n = (16*(\frac{1.2}{(270-264)}))^2

n= 10.24 ≅ 11 pregnant women.

I hope it helps!

6 0
2 years ago
What is the factored form of y=x^3+3x^2-x-3 and what the zeros
PSYCHO15rus [73]
   y = x³ + 3x² - x - 3
   0 = x³ + 3x² - x - 3
   0 = x²(x) + x²(3) - 1(x) - 1(3)
   0 = x²(x + 3) - 1(x + 3)
   0 = (x² - 1)(x + 3)
   0 = (x² + x - x - 1)(x + 3)
   0 = (x(x) + x(1) - 1(x) - 1(1))(x + 3)
   0 = (x(x + 1) - 1(x + 1))(x + 3)
   0 = (x - 1)(x + 1)(x + 3)
   0 = x - 1    or    0 = x + 1    or    0 = x + 3
+ 1      + 1         - 1        - 1         - 3        - 3
   1 = x      or      -1 = x       or      -3 = x

Solution Set: {-3, -1, 1}
3 0
2 years ago
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