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4 years ago

Which is the focus of a parabola with equation y^2=-12x?

Mathematics

2 answers:

solniwko [45]4 years ago

7 0

P is 3 .and its horizontal parabola it's focus is (a-p,b) so (-3,0)

Ksenya-84 [330]4 years ago

6 0

Answer:

Focus of the given parabola is (-3,0)

Step-by-step explanation:

Given equation of parabola is:

y² = -12x

Standard equation of parabola is :

y² = 4px

Parabola opens right or left.

Focus of this parabola is (p,0)

y² = -12x is opens left.

y² = 4(-3)x

Here value of p = -3

So, the focus of given parabola is : (-3,0)

That's the final answer.

I hope its help you.

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3 years ago

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Read 2 more answers

Use the given information to find the minimum sample size required to estimate an unknown population mean μ.

larisa86 [58]

Answer:

The number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.

Step-by-step explanation:

The (1 - α) % confidence interval for population mean is:

$CI=\bar x\pm z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

The margin of error for this interval is:

$MOE= z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

The information provided is:

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*Use a z-table.

Compute the sample size required as follows:

$MOE= z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times \sigma}{MOE}]^{2}$

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Step-by-step explanation:

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