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4 years ago

Which is the focus of a parabola with equation y^2=-12x?

Mathematics

2 answers:

solniwko [45]4 years ago

7 0

P is 3 .and its horizontal <span>parabola it's focus is (a-p,b) so (-3,0)</span>

Ksenya-84 [330]4 years ago

6 0

Answer:

Focus of the given parabola is (-3,0)

Step-by-step explanation:

Given equation of parabola is:

y² = -12x

Standard equation of parabola is :

y² = 4px

Parabola opens right or left.

Focus of this parabola is (p,0)

y² = -12x is opens left.

y² = 4(-3)x

Here value of p = -3

So, the focus of given parabola is : (-3,0)

That's the final answer.

I hope its help you.

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3 years ago

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aleksklad [387]

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Step-by-step explanation:

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3 years ago

36. The price of a new home. According to the U.S. Census

zmey [24]

Answer:

210

Step-by-step explanation:

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4 0

3 years ago

H(x)=-x^2-4 and I(x)=2x+3<br> H(I(s))

ICE Princess25 [194]

Easy peasy
just subsitute I(x) for the x in the h(x) so
h(I(s))=-(2s+3)^2-4
distribute and simplify
h(I(s))=-(4s^2+12s+9)-4
h(I(s))=-4s^2-12s-9-4
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3 0

3 years ago

Simplify the expression a^b: 5x^4 y^2 * 3x^6 y^9

tatyana61 [14]

Answer:

3x(3x + 2)

Step-by-step explanation:

(4x2 - 2x) - (-5x2 - 8x)

= 4x2 - 2x + 5x2 + 8x.

= 4x2 + 5x2 - 2x + 8x.

= 9x2 + 6x.

= 3x(3x + 2).

I hope it is right.

4 0

3 years ago