Question

Which is the focus of a parabola with equation y^2=-12x?

Answer 1

P is 3 .and its horizontal parabola it's focus is (a-p,b) so (-3,0)

Answer 2

Answer:

Focus of the given parabola is (-3,0)

Step-by-step explanation:

Given equation of parabola is:

y² = -12x

Standard equation of parabola is :

y² = 4px  

Parabola opens right or left.

Focus of this parabola is (p,0)

y² = -12x is opens left.

y² = 4(-3)x

Here value of p = -3

So, the focus of given parabola is : (-3,0)

That's the final answer.

I hope its help you.