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3 years ago

Why must the electric field be normal to the surface at every point of a charged conductor?

1 answer:

3 0

-- If the field were inclined to the surface, then it would have
some component parallel to the surface.

-- Then, since we're talking about a conductor, the charges
on the object would move in response to that component
of the field, until there was no longer any component of the
field trying to move them.

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Consider Compton Scattering with visible light.A photon with wavelength 500nm scatters backward(theta=180degree) from a free ele

JulijaS [17]

Answer: $4.86(10)^{-12}m$

Explanation:

The Compton Shift $\Delta \lambda$ in wavelength when photons are scattered is given by the following equation:

$\Delta \lambda=\lambda' - \lambda_{o}=\lambda_{c}(1-cos\theta)$ (1)

Where:

$\lambda'=500 nm=500(10)^{-9} m$ is the wavelength of the scattered photon

$\lambda_{o}$ is the wavelength of the incident photon

$\lambda_{c}=2.43(10)^{-12} m$ is a constant whose value is given by $\frac{h}{m_{e}.c}$ , being $h=4.136(10)^{-15}eV.s$ the Planck constant, $m_{e}$ the mass of the electron and $c=3(10)^{8}m/s$ the speed of light in vacuum.

$\theta=180\°$ the angle between incident phhoton and the scatered photon.

$\Delta \lambda=2.43(10)^{-12} m (1-cos(180\°))$ (2)

$\Delta \lambda=4.86(10)^{-12}m$ (3) This is the shift in wavelength

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3 years ago

What is one way you can destroy a magnet’s magnetism?

Alekssandra [29.7K]

-- heat the magnet red-hot in a flame
-- drop it on the floor several times, or beat it with a hammer
-- place it in a strong, rapidly alternating external magnetic field

7 0

3 years ago

What portion (division) of a meter stick is a centimeter?

Anastasy [175]

A meter is 100 meters. So a hundredth of a meter stick is a centimeter.<span />

8 0

4 years ago

Read 2 more answers

A high-speed flywheel in a motor is spinning at 500 rpm when a power failure suddenly occurs. the flywheel has mass 40.0 kg and

tangare [24]

<span>The flywheel is solid cylindrical disc. Moment of inertial = Â˝ * mass * radius^2 Mass = 40.0 kg Radius = Â˝ * 76.0 cm = 38 cm = 0.38 meter Moment of inertial = Â˝ * 41 * 0.36^2 Convert rpm to radians/second The distance of 1 revolution = 1 circumference = 2 * Ď€ * r The number of radians/s in 1 revolution = 2 * Ď€ 1 minute = 60 seconds 1 revolution per minute = 2 * Ď€ radians / 60 seconds = Ď€/30 rad/s Initial angular velocity = 500 * Ď€/30 = 16.667 * Ď€ rad/s 170 revolutions = 170 * 2 * Ď€ = 340 * Ď€ radians The flywheelâ€™s initial angular velocity = 16.667 * Ď€ rad/s. It decelerated at the rate of 1.071 rad/s^2 for 48.89 seconds. Î¸ = Ď‰i * t + Â˝ * Î± * t^2 Î¸ = 16.667 * Ď€ * 48.89 + Â˝ * -1.071 * 48.89^2 2559.9 - 1280 Î¸ = 1280 radians</span>

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3 years ago

You jump off a truck and accelerate toward the surface of the Earth. Does the Earth accelerate toward you?

Triss [41]

When we jump from the truck and accelerate towards the earth surface, the earth also accelerates towards us but it's acceleration is very negligible.

To find the answer, we need to know about the acceleration of earth due to the gravitational attraction.

<h3>What's the gravitational force between the earth and a person?</h3>

Gravitational attraction force is GMm/r² between the earth and a person.
M= mass of the earth

m= mass of the person

r= separation between them.

<h3>What's the acceleration of the earth towards the person when he jumps from a truck?</h3>

According to Newton's second law, Force = M×acceleration
Acceleration= Force / M
Here, Force = GMm/r²,

so acceleration of earth= Gm/r²

As this acceleration is very small, so we can't notice it.

Thus, we can conclude that the earth also accelerates towards us.

Learn more about the gravitational force here:

brainly.com/question/72250

#SPJ4

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2 years ago