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Anna35 [415]
3 years ago
5

5 A truck travelling at 25 m/s puts on its brakes for 4 s. This produces an acceleration of –2 m/s. What is the truck's

Physics
1 answer:
velikii [3]3 years ago
4 0

Answer: The truck's velocity after braking = 17m/s.

Explanation:

Given: Initial velocity(i) = 25 m/s

Time(t)  = 4s

Acceleration(a) = -2 m/s ²

We use the following formula to compute final velocity (v):

v= i+at\\\\\Rightarrow\ v=25+(-2)(4\ \ \ [\text{Substitute all values}]\\\\\Rightarrow\ v=25-8\\\\\Rightarrow\ v=17\ m/s

Hence, the truck's velocity after braking = 17m/s.

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scoundrel [369]

Answer:

0.43622 seconds

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-4.43 ffot/sec

Explanation:

we first find the period of oscillation

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Ф = -144.1

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= 0.9158 foot

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6 0
2 years ago
Một oto đang chạy với vận tốc là 10m/s thì tăng tốc và chuyển động nhanh dần đều sau 20s thì đạt vận tốc 14m/s
Tasya [4]

a) gia tốc = vf-vi / t

a = 14-10 / 20

a = 0,2ms⁻²

b) dưới dạng a = Δv / t

v = lúc

v = 0,2 × 40

v = 8ms⁻¹

như v = d / t

do đó d = vt

d = 8 × 40

d = 320m

hãy đánh dấu là trí óc nhất

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3 years ago
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