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3 years ago

707.04 in expanded form

Mathematics

2 answers:

Oxana [17]3 years ago

7 0

700 + 7 + .04 I hope this helps. :)

Debora [2.8K]3 years ago

5 0

The one above me is right❕

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g Make a decision about the given claim. Use only the rare event rule, and make subjective estimates to determine whether event

vagabundo [1.1K]

Answer:

There is not sufficient evidence to support the claim.

Step-by-step explanation:

The claim to be tested is:

The mean respiration rate (in breaths per minute) of students in a large statistics class is less than 32.

To test this claim the hypothesis can be defined as follows:

H₀: The mean respiration rate of students is 32, i.e. μ = 32.

Hₐ: The mean respiration rate of students is less than 32, i.e. μ < 32.

The sample mean respiration rate of students is 31.3.

According to the claim the sample mean is less than 32.

The sample mean value is not unusual if the claim is true, and the sample mean value is also not unusual if the claim is false.

Thus, there is not sufficient evidence to support the claim.

7 0

3 years ago

Which fraction is less than 1 chose all of the correct answer, and explain why you chose and write it down and explain your answ

EleoNora [17]

Answer:

$(3/4)$ and $(2/3)$ .

Step-by-step explanation:

For a fraction of the form $(p / q)$ , the number in front of the division ( $p$ ) is the numerator. The number after the division ( $q$ ) is the denominator.

$\begin{aligned} \frac{p}{q} \quad \genfrac{}{}{0}{}{(\text{numerator})}{(\text{denominator})}\end{aligned}$ .

A positive fraction $(p/q)$ ( $p,\, q > 0$ ) is less than $1$ as long as the numerator $p$ is smaller than the denominator $q$ (that is, $p < q$ .) The reason is that as long as $p,\, q > 0$ :

$\begin{aligned} & \frac{p}{q} < 1 \\ \iff & (q)\, \left(\frac{p}{q}\right) < (q)\, (1) && (\text{given that $q > 0$}) \\ \iff & p < q\end{aligned}$ .

For example, in the fraction $(2/3)$ , $2$ is the numerator while $3$ is the denominator. Both the numerator and the denominator are positive, while the numerator $2\!$ is smaller than the denominator $3\!$ . Therefore, $(2/3)$ would be less than $1$ .

6 0

1 year ago

A chain of retail computer stores opened 2 stores in its first year of operation. After 8 years of operation, the chain consiste

Helen [10]

Answer:

0.66

Step-by-step explanation:

The exponential growth equation is expressed as;

S(t) = S0e^kt

S(t) is the number of stores after t years

S0 is the initial number of stores

If a chain of retail computer stores opened 2 stores in its first year of operation then at t = 1, S(t) = 2. Substitute into the equation;

2 = S0e^k(1)

2 = S0e^k .... 1

Also if after 8 years of operation, the chain consisted of 206 stores, this means at t = 8, S(t) = 206. Substitute into the equation;

206 = S0e^k(1)

206 = S0e^8k .... 2

Next is to calculate the value of k

Divide equation 2 by 1;

$\frac{206}{2} = \frac{S0e^{8k} }{S0e^k }\\103 = e^{7k}\\apply \ ln \ to \ both \ sides\\ln103 = lne^{7k}\\ln103 = 7k\\k = \frac{ln103}{7}\\k = \frac{4.6347}{7} \\k = 0.6621$