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HACTEHA [7]
3 years ago
9

Order the following from least to greatest. 1/2, 2%, 2.1 x 10-2, 0.20

Mathematics
1 answer:
Leya [2.2K]3 years ago
8 0

Answer:

Step-by-step explanation:

2%, 0.20, 1/2,  2.1 x 10-2

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Mariulka [41]
The answer is 25:1 or 25 to 1. They are the same thing thought.
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3 years ago
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Is my answer correct??
Studentka2010 [4]

Answer:

<u></u>

  • <u>The correct answer is the first choice: Hinge Theorem.</u>

Explanation:

The <em>Hinge Theorem</em> compares the lengths of two sides of two triangles, given that the other two pairs of sides are congruent and the included angles are different.

The theorem states that if two sides of a triangle are congruent to two sides of another triangle and the included angle of one triangle is greater than the included angle of the other triangle, then length of the third side of the first triangle is greater than the length of the third side of the second triangle.

The figures shows triangles UVT and STV

The angle UVT is greater than the angle STV.

The sides ST and VU are congruent, as the small vertical marks indicate.

The side TV is a common side of both triangles.

Then, you already have that two sides of the triangle STV are congruent to two sides of triangle UVT and the angle UVT is greater than the angle STV.

Hence, by the HInge Theorem the side TU is greater than side SV.

3 0
3 years ago
Rena wrote all the integers from 1 to 12. <br><br> How many numbers did she write?
Aleksandr [31]

Answer:

15

integers from 1 to 9 have only one number each, so in total 9 numbers. integers from 10 to 12 have 2 numbers each, 3*2=6. 9+6=15

7 0
3 years ago
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Which two integers is 115 between?
Lady_Fox [76]

<em><u>Answer:</u></em>

115 is between 114 and 116 because they are the integers that are directly bigger than 115 and smaller than 115.

8 0
3 years ago
Help ASAP
horrorfan [7]

Answer:

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Step-by-step explanation:

30100 have dogs, 18100 have cats.

The question simply asks for a union scenario thus the law of AND & OR is applicable.

Therefore:-Those who have both cats and dogs partially have cats.

P(X=both \ cat \ and \ dog)=\frac{18100}{30100}\\p=\frac{181}{301}

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3 years ago
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