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2 years ago

Please show x < 80 on a number line

Mathematics

1 answer:

nevsk [136]2 years ago

7 0

Answer:

on the number line make an open circle at 80 (am open circle is this: ○) and connect that to an arrow that points back to 0 and the negative numbers. It doesn't matter how far back as long as you make it an arrow

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The hypotenuse of a right triangle has length 50 cm. One leg has length 20 cm. The nearest tenth, what is the length of the othe

Fantom [35]

Answer:

45.8 cm

Step-by-step explanation:

Let the length of other leg be l

By pythagoras theorem,

$l \: = \sqrt{ {50}^{2} - {20}^{2} } \\ l \: = 45.8cm$

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2 years ago

You read 50 pages in an hour your sister reads 40 pages in an hour how many more pages did you read than your sister reads in 1/

Elena-2011 [213]

To start to figure this problem out, we can first figure out how many more pages you read in an hour compared to your sister.

50 - 40 = 10, so you read 10 more pages in 1 hour.

Now we have to figure out how much more you would read in 1/2 an hour. Since 1/2 an hour is 1/2 of an hour, we can divide 10 by 2 to figure out how many more pages you read in an hour compared to your sister. 10 divided by 2 is 5, so you read 5 more pages every half hour.

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3 years ago

Find the unknown side (w) of the rectangular solid. Please help..

Nata [24]

Answer:

W= 2

Step-by-step explanation:

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2 years ago

in a certain pentagon, the interior angles are a,b,c,d,e where a,b,c,d,e are integers strictly less than 180. ("Strictly less th

guajiro [1.7K]

Answer:

least to greatest: {61, 61, 61, 178, 179}

Step-by-step explanation:

If the third-largest angle is 61°, the smallest three angles cannot be larger than 183°. Since the total of all angles must be 540°, and the total of the largest two cannot be greater than 179°×2 = 358°, the sum of the smallest three must be at least 540° -358° = 182°.

So, the possible sets of angles with the smallest 3 totaling 182° or 183° are (in degrees) ...

{60, 61, 61, 179, 179} . . . . two modes

(61, 61, 61, 178, 179} . . . . . one mode -- the set you're looking for

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Answer:

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