All categories

3 years ago

Rewrite each expression by combining like terms. 13p - 4p + 6q

Mathematics

2 answers:

Dovator [93]3 years ago

7 0

Answer:

You answer would be 15p

Step-by-step explanation:

13p - 4p + 6p

9p + 6p

15p

mash [69]3 years ago

6 0

Answer:

9p + 6q

Step-by-step explanation:

Rewrite each expression

Combine like terms

13p - 4p + 6q

_____________________

When we have like terms, we can only add the ones that have the same symbols as endings, such as variables, exponents, etc. Therefore :

Add "p" values together :

13p - 4p

9p.

Now rewrite the expression, we cannot combine like terms with "p" and "q" because they are not the same variable :

9p + 6q

You might be interested in

Select the correct answer. if you roll a single six-sided die, what is the probability of rolling an odd number? a. b. c. d. 3

Mamont248 [21]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

P(odd number)= $\frac{3}{6}$

= $\frac{1}{2}$

5 0

2 years ago

ABCD is a parallelogram such that AB is parallel to DC and DA parallel to CB. The length of side AB is 20 cm. E is a point betwe

Firdavs [7]

The length of DF will be 17 cm.

5 0

3 years ago

Read 2 more answers

Solve for y? y/4-y+1/5=y+2/8 A)y=-4 B)y=-11/3 C)y=18/7 D)y=-6

vichka [17]

Answer:

d) y = -6

Step-by-step explanation:

5 0

3 years ago

What is the modulus and argument after (StartRoot 3 EndRoot) (cosine (StartFraction pi Over 18 EndFraction) + I sine (StartFract

fgiga [73]

Answer:

$|z| = 27$ -- Modulus

$\theta = \frac{\pi}{3}$ --- Argument

Step-by-step explanation:

Given

$((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6$

Required

Determine the modulus and the argument

We have that:

$z = ((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6$

Expand:

$z = (\sqrt 3)^6(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$

$z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$

A complex equation can be expressed as:

$z = |z| e^{i\theta}$

Where

$|z| = modulus$

$\theta = argument$

Where

$e^{i\theta} = (cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})$

So:

$z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$ becomes

$z = 27(e^{i\frac{\pi}{18}})^6$

By comparison:

$e^{i\theta} = (e^{i\frac{\pi}{18}})^6$

This gives:

${i\theta} = i\frac{\pi}{18}}*6$

${i\theta} = i\frac{6\pi}{18}}$

${i\theta} = i\frac{\pi}{3}}$

Divide through by i

$\theta = \frac{\pi}{3}$

Hence, the modulus, z is:

$|z| = 27$

And the argument $\theta$ is

$\theta = \frac{\pi}{3}$

4 0

3 years ago

Help! Please answer screen shot! Brainliest, stars, and hearts! Please help!

lutik1710 [3]

Answer:

since 0=noon

and 15 secs=25% of a min

plot the point on the very first line to the right of 0

(the tiny line)

Step-by-step explanation:

8 0

3 years ago