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Gwar [14]
3 years ago
14

I need help with this ASAP please

Mathematics
1 answer:
Leviafan [203]3 years ago
8 0

Answer:

Uhhh try downloading.... Conects... ¯\_(ツ)_/¯

Step-by-step explanation:

....*whispers* Your welcome....

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Can somebody please help me on this?
daser333 [38]

Answer:

6,12,15,18

Step-by-step explanation:

in my answer I multiplied each x with 3 and then divided i am not sure how you would do it but normally we would multiply

7 0
2 years ago
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Average rate of change help!!
frez [133]

Given that the function is f(x)=x^{3}-6 x^{2}+4 x+7

We need to determine the average rate of change over the interval 0 \leq x \leq 5

<u>Value of f(x) when x = 0:</u>

Substituting x = 0 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(0)=(0)^{3}-6 (0)^{2}+4 (0)+7

f(0)=0-0+0+7

f(0)=7

Thus, the value of f(0) is 7.

<u>Value of f(x) when x = 5:</u>

Substituting x = 5 in the function f(x)=x^{3}-6 x^{2}+4 x+7, we have;

f(5)=(5)^{3}-6 (5)^{2}+4 (5)+7

f(5)=125-150+20+7

f(5)=2

Thus, the value of f(5) is 2.

<u>Average rate of change:</u>

The average rate of change can be determined using the formula,

Rate \ of \ change=\frac{f(b)-f(a)}{b-a}

where a=0 and b=5

Thus, we have;

Rate \ of \ change=\frac{f(5)-f(0)}{5-0}

Rate \ of \ change=\frac{2-7}{5-0}

Rate \ of \ change=\frac{-5}{5}

Rate \ of \ change=-1

Thus, the average rate of change over the interval 0 \leq x \leq 5 is -1.

3 0
2 years ago
Evaluate x(y+3)/(3+y)z for x=12, y=1, and z=6.<br><br> A) 2<br><br> B) 5<br><br> C) 8<br><br> D) 6
fgiga [73]

Answer:

2

Step-by-step explanation:

We take the equation

x(y+3)/(3+y)z

and substitute the values for each individual variable in the problem. It looks like this:

12(1+3)/(3+1)6

Now we can solve the equation.

When solved, it equals 2.

5 0
3 years ago
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Kelly practiced her flute for 30 minutes a day for 9 days. How many total minutes did she practice?
Lesechka [4]
she practice 270 minutes
7 0
2 years ago
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Which of the following functions is graphed below.
Valentin [98]

Answer: Option A

y=\left \{ {{x^2 +2;\ \ x

Step-by-step explanation:

In the graph we have a piecewise function composed of a parabola and a line.

The parabola has the vertex in the point (0, 2) and cuts the y-axis in y = 2.

The equation of this parabola is y = x ^ 2 +2

Then we have an equation liney = -x + 2&#10;

Note that the interval in which the parabola is defined is from -∞ to x = 1. Note that the parabola does not include the point x = 1 because it is marked with an empty circle " о ."

(this is x< 1)

Then the equation of the line goes from x = 1 to ∞ . In this case, the line includes x = 1 because the point at the end of the line is represented by a full circle .

(this is x\geq 1)

Then the function is:

y=\left \{ {{x^2 +2;\ \ x

7 0
3 years ago
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