<span>The magnetic field of the Earth serves a useful purpose in deflecting Solar radiation. Without the magnetic field there is much more charged-particle radiation striking the surface. The auroras would occur everywhere instead of at the magnetic poles. Compass needles wouldn't work, and then they would flip direction.. The magnetic field IS DECREASING and could go to zero and reverse sometime in the next few tens-of-thousands of years.</span>
Holding
temperature and pressure constant
<span>the
most important feature in determining the phase of a given organic compound is
pressure. ransfers of organic compounds
between phases are controlled by molecular interactions (intermolecular bonding)
in the two phases between which transfer is occurring. This is governed
by temperature and pressure</span>
Answer: Magnesium Mg
Explanation:
Oxidization is the process by which a substance either gains oxygen or losses electrons.
The chemical reaction of the above is denoted by,
Mg(s) + 2HCl(aq) -----> MgCl2(aq) + H2(g)
Mg went from a 0 to a +2 state which would mean that it lost electrons.
It was therefore oxidized.
Please do react or comment if you need clarification or if the answer helped you. This can help other users as well. Thank you.
The molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.
<h3>How to calculate molarity?</h3>
The molarity of a solution can be calculated using the following formula:
Molarity = no of moles/volume
According to this question, a solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water.
no.of moles of CuSO4 = 35g ÷ 159.6g/mol
no. of moles of CuSO4 = 0.22 moles
Therefore; molarity of CuSO4 solution is calculated as follows:
M = 0.22 ÷ 0.25
M = 0.88M
Therefore, the molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.
Learn more about molarity at: brainly.com/question/12127540
During the reaction of glucose and fructose with excess phenylhydrazine to form osazone, only the C-1andC-2 atoms of glucose and fructose participate in the reaction. The rest of the molecule remains intact. Hence, glucose and fructose produce the same osazone.
