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Zanzabum
3 years ago
6

Choose the number of significant figures indicated. 0.078

Chemistry
2 answers:
Feliz [49]3 years ago
5 0

Answer : The number of significant figures are, two

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

  1. Digits from 1 to 9 are always significant.
  2. All non-zero numbers are always significant. For example: 654, 6.54 and 65.4 all have three significant figures.
  3. All zero’s between integers are always significant. For example: 5005, 5.005 and 50.05 all have four significant figures.
  4. All zero’s preceding the first integers are never significant. For example: 0.0078 has two significant figures.
  5. All zero’s after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures.

The give number is, 0.078

By using rule 4, we get the number of significant figures which are '7' and '8' that means the number of significant figures are, 2

Hence, the number of significant figures are, two

MAXImum [283]3 years ago
4 0
2 significant figures
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Calculating molarity using solute moles A chemist prepares a solution of sodium chloride (NaCl) by measuring out 6.89 mol of sod
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Answer: Concentration of the chemist's sodium chloride solution is 34.4 mol/L.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

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volume of solution = 200 ml

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In a process for producing acetic acid, oxygen gas is bubbled into acetaldehyde, CH3CHO, containing manganese(II) acetate (catal
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<u>Answer:</u> The mass of acetic acid that can be produced is 30.24 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For acetaldehyde:</u>

Given mass of acetaldehyde = 22.2 g

Molar mass of acetaldehyde = 44 g/mol

Putting values in equation 1, we get:

\text{Moles of acetaldehyde}=\frac{22.2g}{44g/mol}=0.504mol

  • <u>For oxygen gas:</u>

Given mass of oxygen  gas = 12.6 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{12.6g}{32g/mol}=0.394mol

The given chemical equation follows:

2CH_3CHO(l)+O_2(g)\rightarrow 2CH_3COOH(l)

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2 moles of acetaldehyde reacts with 1 mole of oxygen gas

So, 0.504 moles of acetaldehyde will react with = \frac{1}{2}\times 0.504=0.252mol of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, acetaldehyde is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of acetaldehyde produces 2 moles of acetic acid

So, 0.504 moles of acetaldehyde will produce = \frac{2}{2}\times 0.504=0.504moles of acetic acid

Now, calculating the mass of acetic acid from equation 1, we get:

Molar mass of acetic acid = 60 g/mol

Moles of acetic acid = 0.504 moles

Putting values in equation 1, we get:

0.504mol=\frac{\text{Mass of acetic acid}}{60g/mol}\\\\\text{Mass of acetic acid}=(0.504mol\times 60g/mol)=30.24g

Hence, the mass of acetic acid that can be produced is 30.24 grams

8 0
3 years ago
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