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bogdanovich [222]
2 years ago
13

How many dL in 1,000 mL

Chemistry
2 answers:
Elena-2011 [213]2 years ago
7 0

you asked this question twice but the answer is 10 dL

Anna007 [38]2 years ago
6 0

1,000 mL is the same as 10 dL.

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14. Compare between the plasticity of edge and screw dislocations in BCC metals 15. Why does a screw dislocation in a BCC metal
Alenkasestr [34]

Answer:

14) The edge dislocation is more plastic than the screw dislocation

15) So as to form kinks that are fast moving

Explanation:

14) Edge and screw dislocations are the two main types of mobile dislocations

The three dimensional core of the screw dislocation prevents the slipping of the layers (one over the other) in a BCC metal such that kinks are required to be formed first  by thermal activation (heating) in order. The kinks are edge dislocation that move such that the screw dislocation moves forward

Hence, the edge dislocation is more plastic than the screw dislocation

15) The three dimensional structure of a screw dislocation acts like a wedge which resists the slipping of the layers in the BCC structure such that the screw dislocation needs to be highly thermally activated forming kinks before the surrounding layers can move.

4 0
2 years ago
My teacher never taught me how to do this helpppp!!!!!!!
djverab [1.8K]
Just search up how much the weight is equal to another, then multiply it, thats what i do lol sorry if im no help
6 0
3 years ago
A 48.0g sample of quartz, which has a specific heat capacity of 0.730·J·g−1°C−1, is dropped into an insulated container containi
Butoxors [25]

Answer:

The equilibrium temperature of the water is 26.7 °C

Explanation:

<u>Step 1:</u> Data given

Mass of the sample quartz = 48.0 grams

Specific heat capacity of the sample = 0.730 J/g°C

Initial temperature of the sample = 88.6°C

Mass of the water = 300.0 grams

Initial temperature = 25.0°C

Specific heat capacity of water = 4.184 J/g°C

<u>Step 2:</u> Calculate final temperature

Qlost = -Qgained

Qquartz = - Qwater

Q =m*c*ΔT

Q = m(quartz)*c(quartz)*ΔT(quartz) = -m(water) * c(water) * ΔT(water)

⇒ mass of the quartz = 48.0 grams

⇒ c(quartz) = the specific heat capacity of quartz = 0.730 J/g°C

⇒ ΔT(quartz) = The change of temperature of the sample = T2 -88.6 °C

⇒ mass of water = 300.0 grams

⇒c(water) = the specific heat capacity of water = 4.184 J/g°C

⇒ ΔT= (water) = the change in temperature of water = T2 - 25.0°C

48.0 * 0.730 * (T2-88.6) -300.0 * 4.184 *(T2 - 25.0)

35.04(T2-88.6) = -1255.2 (T2-25)

35.04T2 -3104.544 = -1255.2T2 + 31380

1290.24T2 = 34484.544

T2 = 26.7 °C

The equilibrium temperature of the water is 26.7 °C

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If you pump air into cycle tyre a slight warming effect is noticed at valve stem why
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