How many dL in 1,000 mL
2 answers:
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Answer : The mass of required is, 166.4 grams.
Explanation :
First we have to calculate the moles of nitrogen gas.
Using ideal gas equation:
where,
P = Pressure of gas = 1.00 atm
V = Volume of gas = 113 L
n = number of moles = ?
R = Gas constant =
T = Temperature of gas =
Putting values in above equation, we get:
Now we have to calculate the moles of sodium azide.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 3 mole of produced from 2 mole of
So, 3.84 moles of produced from
moles of
Now we have to calculate the mass of
Molar mass of = 65 g/mole
Therefore, the mass of required is, 166.4 grams.