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Juli2301 [7.4K]
3 years ago
10

Consider the equations below. (1) Ca(s) + CO2(g) + 1 2 O2(g) → CaCO3(s) (2) 2Ca(s)+O2(g) → 2CaO(s) How should you manipulate the

se equations so that they produce the equation below when added? Check all that apply. CaO(s) + CO2(g) → CaCO3(s) reverse the direction of equation (2) multiply equation (1) by 3 multiply equation (2) by 1/2
Chemistry
1 answer:
In-s [12.5K]3 years ago
3 0

Answer : The correct options are, reverse the direction of equation (2) and multiply equation (2) by 1/2.

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation.

The main given balanced chemical reaction is,

CaO(s)+CO_2(g)\rightarrow CaCO_3(s)

Now we have to determine the main chemical reaction from the given two intermediate reactions.

(1) Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\rightarrow CaCO_3(s)

(2) 2Ca(s)+O_2(g)\rightarrow 2CaO(s)

Now reverse the equation (2), multiply equation (2) by 1/2 and then add both the equations, we get the main chemical reaction.

(1) Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\rightarrow CaCO_3(s)

(2) CaO(s)\rightarrow Ca(s)+\frac{1}{2}O_2(g)

Now add both the equations, we get:

CaO(s)+CO_2(g)\rightarrow CaCO_3(s)

Hence, the steps used for the main reaction are, reverse the direction of equation (2) and multiply equation (2) by 1/2.

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2 years ago
How many grams of He are necessary to fill a balloon having a volume of 4.50 × 10^{3} mL to a pressure of 1.14 × 10^{3} torr at
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The mass in grams of He are necessary to fill a balloon having a volume of 4.50×10³ mL to a pressure of 1.14×10³ torr at 25.0ºC is 1.104 grams.

<h3>How do we calculate the grams from moles?</h3>

Mass (W) in grams from moles (n) will be calculated by using the below equation:
n = W/M, where

M = molar mass

Moles of helium gas will be calculated by using the ideal gas equation:

PV = nRT, where

R = universal gas constant = 62.363 L.torr / K.mol

P = pressure of gas = 1.14×10³ torr

V = volume of gas = 4.50×10³ mL = 4.50 L

n = moles of gas = ?

T = temperature = 25.0ºC = 298 K

On putting these values on the ideal gas equation, we get

n = (1140)(4.5) / (62.363)(298) = 5130 / 18584

n = 0.276 moles

Now we convert this moles into mass by using the first equation as:

W = (0.276mol)(4g/mol) = 1.104 g

Hence required mass of helium gas is 1.104 grams.

To know more about ideal gas equation, visit the below link:

brainly.com/question/12873752

#SPJ1

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