Hey there!
Atomic mass Bromine ( Br ) = 79.9 u
Therefore:
79.9 g Br --------------- 22.4 L ( at STP )
18.0 g Br --------------- volume ??
Volume Br = 18.0 * 22.4 / 79.9
Volume Br = 403.2 / 79.9
Volume Br = 5.046 L
hope this helps!
Explanation:
Bernoulli equation for the flow between bottom of the tank and pipe exit point is as follows.
= 
![\frac{(100 \times 144)}{62.43} + 0 + h[tex] = [tex]\frac{(50 \times 144)}{(62.43)} + \frac{(70)^{2}}{2(32.2)} + 0 + 40 + 60](https://tex.z-dn.net/?f=%5Cfrac%7B%28100%20%5Ctimes%20144%29%7D%7B62.43%7D%20%2B%200%20%2B%20h%5Btex%5D%20%3D%20%5Btex%5D%5Cfrac%7B%2850%20%5Ctimes%20144%29%7D%7B%2862.43%29%7D%20%2B%20%5Cfrac%7B%2870%29%5E%7B2%7D%7D%7B2%2832.2%29%7D%20%2B%200%20%2B%2040%20%2B%2060)
h = 
= 60.76 ft
Hence, formula to calculate theoretical power produced by the turbine is as follows.
P = mgh
= 
= 6076 lb.ft/s
= 11.047 hp
Efficiency of the turbine will be as follows.
=
× 100%
=
= 52.684%
Thus, we can conclude that the efficiency of the turbine is 52.684%.
Answer:
2.03125g of acetylene
Explanation:
First thing's first, we have to write out the balanced chemical equation;
CaC2(s) + 2H2O(l) → Ca(OH)2(aq) + C2H2(g)
Water is in excess, so CAC2 is our limiting reactant. i.e it determines the amount of product that would be formed.
1 mol of CaC2 produces 1 mol of C2H2
In terms of mass;
Mass = Number of moles * Molar mass
where the molar mass of the elements are;
Ca = 40g/mol
C = 12g/mol
H = 1g/mol
CaC2 = 40+ (2*12) = 64g/mol
C2H2 =( 2 * 12) + ( 2 * 1) = 26g/mol
64g (1 * 64g/mol) of CaC2 produces 26g ( 1mol * 26g/mol) of C2H2
5g would produce x?
64 = 26
5 = x
Upon solving for x we have;
x = (5 * 26) / 64
x = 2.03125g
The given alkyne is Option A 3-heptyne
<h3>
What is an Alkyne ?</h3>
The hydrocarbon having at least one C-C triple bond is called an Alkyne.
It has the general formula of
.
In the question it is being mentioned that it is an alkyne so there will be a triple bond and not a double bond.
It has been asked in the question that
CH3CH₂C ≡ CCH₂CH₂CH3 is which alkyne from the given option.
The counting of the Carbon chain is done from the left side and the Triple bond is at the 3rd Carbon , so 3-heptyne .
To know more about Alkyne
brainly.com/question/23508203
#SPJ1
<h3 />