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3 years ago

Explain what Happens at the saturation point when adding salt to water at room temperature.

Chemistry

1 answer:

lorasvet [3.4K]3 years ago

6 0

Answer:

See below

Step-by-step explanation:

You won't see much happening. The solution is saturated, so the salt will fall to the bottom of the container and sit there. It will not dissolve.

However, at the atomic level, Na⁺ and Cl⁻ ions are being pulled from the surface of the crystals and going into solution as hydrated ions. At other places, Na⁺ and Cl⁻ ions are returning to the surface of the crystals.

The process is

NaCl(s) ⇌ Na⁺(aq) + Cl⁻(aq)

The rates of the forward and reverse processes are equal, so you see no net change.

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In the equation below, which of the following is true? 2Fe + 6HBr yields 2FeBr3 + 3H2

eimsori [14]

2Fe+ 6HBr ---> 2FeBr3 +3H2
Fe is a reducing agent is what that is true in equation above This is because it oxidation state move from zero to positive three.Reducing agent is an element or compound that loses or donate an electron to another chemical species in a redox chemical reaction. Fe is oxidized since it loses electron in the redox reaction

8 0

3 years ago

A 50.0 mL sample containing Cd2+ and Mn2+ was treated with 56.3 mL of 0.0500 M EDTA. Titration of the excess unreacted EDTA requ

egoroff_w [7]

Answer:

The concentration of Cd2+ is 0.0175 M

The concentration of Mn2+ is 0.0305 M

Explanation:

Step 1: Data given

A 50.0 mL sample contains Cd2+ and Mn2+

volume of 0.05 M EDTA = 56.3 mL

Titration of the excess unreacted EDTA required 13.4 mL of 0.0310 M Ca2+.

Titration of the newly freed EDTA required 28.2 mL of 0.0310 M Ca2+

Step 2: Calculate mole ratio

The reaction of EDTA and any metal ion is 1:1, the number of mol of Cd2+ and Mn2+ in the mixture equals the total number of mol of EDTA minus the number of mol of EDTA consumed in the back titration with Ca2+:

Step 3: Calculate total mol of EDTA

Total EDTA = (56.3 mL EDTA)(0.0500 M EDTA) = 0.002815 mol EDTA

Consumed EDTA = 0.002815 mol – (13.4 mL Ca2+)(0.0310 M Ca2+) = 0.002815 - 0.0004154 = 0.0023996 mol EDTA

Step 4: Calculate total moles of CD2+ and Mn2+

So, the total moles of Cd2+ and Mn2+ must be 0.0023996 mol

Step 5: Calculate remaining moles of Cd2+

The quantity of cadmium must be the same as the quantity of EDTA freed after the reaction with cyanide:

Moles Cd2+ = (28.2 mL Ca2+)(0.0310 M Ca2+) = 0.0008742 mol Cd2+.

Step 6: Calculate remaining moles of Mn2+

The remaining moles must be Mn2+: 0.0023996 - 0.0008742 = 0.0015254 moles Mn2+

Step 7: Calculate initial concentrations

The initial concentrations must have been:

(0.0008742 mol Cd2+)/(50.0 mL) = 0.0175 M Cd2+

(0.0015254 mol Mn2+)/(50.0 mL) = 0.0305 M Mn2+

The concentration of Cd2+ is 0.0175 M

The concentration of Mn2+ is 0.0305 M

4 0

3 years ago

H₂SO₄ is considered to be

uranmaximum [27]

Answer:

sulfuric acid

Explanation:

a strong acid that soluble in water.

6 0

3 years ago

What is the cell wall & the chloroplasts?

adoni [48]

The cell wall is mixed with the cell membrane, the cell wall is outside of the membrane and the cell membrane is letter i which allows materials to pass in and out of the cell.

Chloroplasts are letter k they basically just help the plant use photosynthesis.

cell wall: f

chloroplasts: k

6 0

4 years ago

Balance the equation and identify the type of reaction for ? P4(s) + ? Ca(s) → ? Ca3P2(s). 1. 2; 6; 2 — decomposition 2. 2; 6; 2

pishuonlain [190]

Answer:

4. 1; 6; 2 — synthesis

Explanation:

Decomposition reaction is defined as the reaction in which a single large substance breaks down into two or more smaller substances.

$AB\rightarrow A+B$

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

$A+BC\rightarrow AC+B$