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3 years ago

This equation has one solution. 5(x – 1) + 3x = 7(x + 1) What is the solution?

2 answers:

5 0

Open up the brackets
$5x - 5 + 3x = 7x + 7$
Collect like terms
$5x + 3x - 7x = 7 + 5$
Simplify
$8x -7x = 12$
$x = 12$
Therefore, your answer is 12.

TEA [102]3 years ago

3 0

Answer:

x = 12

Step-by-step explanation:

Distribute the parenthesis on both sides of the equation

5x - 5 + 3x = 7x + 7

8x - 5 = 7x + 7 ( subtract 7x from both sides )

x - 5 = 7 ( add 5 to both sides )

x = 12

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3 years ago

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2 years ago

If sin ⁡x=725, and 0 ∠ x ∠ pi/2, what is the tan (x - pi/4)

krok68 [10]

$Tan(x-\frac{\pi }{4}) = \frac{-17}{31}$

<u>Step-by-step explanation:</u>

Here we have , sin ⁡x=7/25( given sin x = 725 which is not possible ) , $0$ . Let's find tan (x - pi/4):

⇒ $Tanx = \frac{sinx}{cosx}$

⇒ $Tanx = \frac{sinx}{\sqrt{1-(sinx)^{2}}}$

⇒ $Tanx = \frac{\frac{7}{25}}{\sqrt{1-(\frac{7}{25})^{2}}}$

⇒ $Tanx = {\frac{7}{25}}{\sqrt{(\frac{625}{625-49})^{}}}$

⇒ $Tanx = {\frac{7}{25}}(\frac{25}{24} )$

⇒ $Tanx = {\frac{7}{24}}$

Now , $Tan(x-\frac{\pi }{4}) = \frac{Tanx - Tan(\frac{\pi }{4} )}{1+ Tanx(Tan(\frac{\pi }{4} )}$

⇒ $Tan(x-\frac{\pi }{4}) = \frac{Tanx -1}{1+ Tanx(1)}$

⇒ $Tan(x-\frac{\pi }{4}) = \frac{\frac{7}{24} -1}{1+\frac{7}{24} }$

⇒ $Tan(x-\frac{\pi }{4}) = \frac{\frac{7-24}{24} }{\frac{7+24}{24} }$

⇒ $Tan(x-\frac{\pi }{4}) = \frac{-17}{24} (\frac{24}{31} )$

⇒ $Tan(x-\frac{\pi }{4}) = \frac{-17}{31}$

7 0

3 years ago

1) For question 1, use the figure below. a) Are the following polygons similar? Explain. (2 pts) Yes or No b) Assume the polygon

Delvig [45]

Answer: a) Yes b) Polygon ABCD ~ Polygon EFGH c) JKLM is 3x bigger than polygon ABCD

Step-by-step explanation:

(for part c)

JM= 36

AD= 12

36/12= 3

JKLM is 3x bigger than polygon ABCD

3 0

3 years ago