Name one way in which oxygen from the air reacts slowly with another materal

Baking soda (NaHCO3) and vinegar (HC2H3O2) react to form sodium acetate, water, and carbon dioxide. If 42.00 g of baking soda re

Setler [38]

Answer:

0.5 mole of CO₂.

Explanation:

We'll begin by calculating the number of mole in 42 g of baking soda (NaHCO₃). This can be obtained as follow:

Mass of NaHCO₃ = 42 g

Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)

= 23 + 1 + 12 + 48

= 84 g/mol

Mole of NaHCO₃ =?

Mole = mass / molar mass

Mole of NaHCO₃ = 42/84

Mole of NaHCO₃ = 0.5 mole

Next, balanced equation for the reaction. This is given below:

NaHCO₃ + HC₂H₃O₂ → NaC₂H₃O₂ + H₂O + CO₂

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂

Finally, we shall determine the number of mole of CO₂ produced by the reaction of 42 g (i.e 0.5 mole) of NaHCO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.

Therefore, 0.5 mole of NaHCO₃ will also react to produce 0.5 mole of CO₂.

Thus, 0.5 mole of CO₂ was obtained from the reaction.

7 0

3 years ago

Please help I will reward brainly THERE ARE 3 ANSWERS

elena-s [515]

ATP is formed

NADH releases electrons

Oxygen Accepts electrons

8 0

3 years ago

Read 2 more answers

To classify a substance as an Arrhenius acid or base, or as a Brønsted-Lowry acid or base, you must consider how the substance b

aleksandr82 [10.1K]

Answer:

Ammonia is an Arrhenius base and a Brønsted-Lowry base.

Explanation:

An Arrhenius base is any substance which, when it is dissolved in an aqueous solution, produces hydroxide (OH^-), ions in solution. An aqueous solution is a solution that has water present in it.

A Bronsted-Lowry base is a substance that accepts a proton, that is, a hydrogen ion (H^+).

Looking at the equation above, ammonia satisfies both characteristics. We can see that when ammonia is dissolved in water, hydroxide ions is produced in the solution. Hence it is an Arrhenius base. Similarly, the hydroxide ion is formed when ammonia accepts a proton. This is a characteristic of a Brownstead-Lowry base. Hence ammonia is both an Arrhenius base and a Brownstead-Lowry base.

4 0

4 years ago

Chlorine has 17 total electrons with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5. What are the first two quantum numbers for

nasty-shy [4]

Answer:

Chlorine has 17 total electrons with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5.

What are the first two quantum numbers for the six electrons in the 2p subshell?

Explanation:

The principal quantum number represents the shell number in which the electron is present.

It is represented with "n".

The next quantum number is the azimuthal quantum number.

It represents the shape of the orbital.

It has values from 0 to (n-1).

Its value depends on the principal quantum number.

Chlorine has 17 total electrons with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5.

For the six elecetrons in 2p subshell:

The first two quantum number values are the same and their values are:

n=2 , l=1.

7 0

3 years ago

Calculate the mass of hydrogen formed when 27 g of aluminum reacts with excess hydrochloric acid according to the balanced equat

Alex

6.069 grams is the mass of hydrogen formed when 27 g of aluminum reacts with excess hydrochloric acid.

Explanation:

Balanced equation for the reaction:

2 Al + 6 HCl → 2 AlCl₃ + 3 H₂

data given:

mass of aluminum = 27 grams

atomic mass of one mole of aluminum = 26.89 grams/mole

formula to calculate number of moles:

number of moles = $\frac{mass}{atomic mass of one mole}$

number of moles = $\frac{27}{26.89}$

= 1.004 moles of aluminum will react

from the balanced equation:

2 moles of Al reacted to form 3 moles of H2

1.004 moles of Al will produce x moles of H2

$\frac{3}{2}$ = $\frac{x}{1.004}$

x = 3.012 moles of H2 will be formed.

mass will be calculated as number of moles multiplied by atomic weight

mass of 3.012 moles of hydrogen ?(atomic weight of one mole H2 = 2.015 grams)

= 3.012 x 2.015

= 6.069 grams of H2 will be formed.

6 0

3 years ago