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andrew11 [14]
4 years ago
8

In this unbalanced reaction, which atom is reduced? h2o + cl2 + so2 → hcl + h2so4

Chemistry
2 answers:
Mariulka [41]4 years ago
5 0
The balanced equation for the above reaction is 
H₂O + Cl₂ + SO₂ ---> HCl + H₂SO₄
redox reactions are made of reduction and oxidation reactions.
reduction is when the oxidation state of the species reduces and in oxidation the oxidation state increases in the species.
in the above reaction,
oxidation state of Cl in Cl₂ is 0
and oxidation state of Cl in HCl is -1
theres a reduction in oxidation number of Cl from 0 to -1.
therefore Cl is reduced in the reaction 
mr_godi [17]4 years ago
5 0

Explanation:

Reduction means the gain of electrons or decrease in number of oxidation state of an atom.

For example, H_{2}O + Cl_{2} + SO_{2} \rightarrow HCl + H_{2}SO_{4}

Reduction half reaction: Cl_{2} + 1e^{-} \rightarrow Cl^{-1}

Here oxidation state of chlorine changes from 0 to -1, that is, chlorine is reducing in this chemical reaction.

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Explanation:

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8 0
3 years ago
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How do molecules of butene form polybutene?
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5 0
3 years ago
Which answer choice lists the number and type of elements in a compound in the way that is close to their actual arrangement?
alexandr1967 [171]

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6 0
3 years ago
.The vapor pressure of a volatile liquid can be determined by slowly bubbling a known volume of gas through it at a known temper
Elis [28]

Explanation:

It is given that the initial mass of benznene is 7.9286 g

Mass of benzene left = 5.9987 g

So, mass of benzene with which gas get saturated will be calculated as follows.

               = 7.9286 g  - 5.9987 g  = 1.9299 g

Therefore, moles of benzene with which gas get saturated = \frac{mass}{ molar mass}

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                = 0.0247 moles

Temperature = 27.3^{o}C = 27.3 + 273.15 = 300.45 K

Volume = 5.01 L

So, according to ideal gas equation PV = nRT

Putting the given values into the ideal gas equation as follows.

                       PV = nRT

           P \times 5.01 L = 0.0247 mol \times 62.36 torr-liter/mol K \times 300.45 K

                   P = \frac{462.781 torr-liter}{5.01 L}

                      = 92.371 torr

Hence, we can conclude that vapor pressure of benzene is 92.371 torr.

8 0
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