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1 year ago

Nitrogen gas was collected by water displacement. What was pressure of the N, collected if the temperature was 22 °C?

Chemistry

1 answer:

Anestetic [448]1 year ago

5 0

The pressure of the N₂ collected if the temperature was 22°C celcius is 98.6823 kPa.

What is atmospheric pressure?

The air around you has weight, and it presses against everything it touches. That pressure is called atmospheric pressure, or air pressure.

Atmospheric pressure = 101.325 kPa

Vapor pressure of water at 22°C = 2.6427 kPa

Pressure of N₂ = (Atmospheric pressure) - (vapour pressure of water at 22°C)

Pressure of N₂ = (101.325 kPa) - ( 2.6427 kPa)

Pressure of N₂ = 98.6823 kPa

Therefore, the pressure of the N₂ collected if the temperature was 22°C celcius is 98.6823 kPa.

Learn more about atmospheric pressure here:

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How many grams of sodium acetate ( molar mass = 83.06 g/mol ) must be added to 1.00 Liter of a 0.200 M acetic acid solution to m

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Answer: The mass of sodium acetate that must be added is 30.23 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

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Volume of solution = 1 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of acetic acid}}{1L}\\\\\text{Moles of acetic acid}=(0.200mol/L\times 1L)=0.200mol$

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{salt}]}{[\text{acid}]})$

$pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of acetic acid = 4.74

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$[CH_3COOH]=0.200mol$

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Putting values in above equation, we get:

$5=4.74+\log(\frac{[CH_3COONa]}{0.200})$

$[CH_3COONa]=0.364mol$

To calculate the mass of sodium acetate for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of sodium acetate = 83.06 g/mol

Moles of sodium acetate = 0.364 moles

Putting values in above equation, we get:

$0.364mol=\frac{\text{Mass of sodium acetate}}{83.06g/mol}\\\\\text{Mass of sodium acetate}=(0.364mol\times 83.06g/mol)=30.23g$

Hence, the mass of sodium acetate that must be added is 30.23 grams

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Answer:

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Well first, let's convert years into months

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In fraction form we would write this as 10/24

If the question asks for it to be simplified, then simply

Both 10 and 24 evenly fit 2

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10 ÷ 2 / 24 ÷ 2

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This can no longer be simplified

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if it undergoes ozonolysis, it gives ethanal and methanal.

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Nitrogen gas was collected by water displacement. What was pressure of the N, collected if the temperature was 22 °C?​

Nitrogen gas was collected by water displacement. What was pressure of the N, collected if the temperature was 22 °C?