<u>Answer:</u> The value of work for the system is -935.23 J
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Given mass of sodium azide = 16.5 g
Molar mass of sodium azide = 65 g/mol
Putting values in above equation, we get:
The given chemical equation follows:
By Stoichiometry of the reaction:
2 moles of sodium azide produces 3 moles of nitrogen gas
So, 0.254 moles of sodium azide will produce = of nitrogen gas
To calculate volume of the gas given, we use the equation given by ideal gas, which follows:
where,
P = pressure of the gas = 1.00 atm
V = Volume of the gas = ?
T = Temperature of the gas =
R = Gas constant =
n = number of moles of nitrogen gas = 0.381 moles
Putting values in above equation, we get:
To calculate the work done for expansion, we use the equation:
We are given:
P = pressure of the system = (Conversion factor: 1 atm = 101325 Pa)
= change in volume = (Conversion factor: )
Putting values in above equation, we get:
Hence, the value of work for the system is -935.23 J