What elements does lithium resemble when it loses 1 electron?
1 answer:
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Complete question:
A spirit burner used 1.00 g methanol to raise the temperature of 100.0 g water in a metal can from 28.00C to 58.0C. Calculate the heat of combustion of methanol in kJ/mol.
Answer:
the heat of combustion of the methanol is 402.31 kJ/mol
Explanation:
Given;
mass of water, = 100 g
initial temperature of water, t₁ = 28 ⁰C
final temperature of water, t₂ = 58 ⁰C
specific heat capacity of water = 4.184 J/g⁰C
reacting mass of the methanol, m = 1.00 g
molecular mass of methanol = 32.04 g/mol
number of moles = 1 / 32.04
= 0.0312 mol
Apply the principle of conservation of energy;
Therefore, the heat of combustion of the methanol is 402.31 kJ/mol
Answer:
E) Silver, mass = 420 g, d = 10.5 g/cm.
Explanation:
Hello,
In this case, since the density is defined by:
Given the mass and density, we compute the volume via:
Thus, for each vase we have:
A)
B)
C)
D)
E)
In such a way, the largest volume corresponds to E) Silver, mass = 420 g, d = 10.5 g/cm.
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