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3 years ago

3 point different between fundamental units and derived units

Chemistry

2 answers:

ivolga24 [154]3 years ago

8 0

Answer:

Fundamental Units:

1) Fundamental units also called base units are used to describe base quantities

2) They cannot be expressed in terms of derived units.

3) Examples : Meter, Ampere, Second etc.

Derived Units:

1) Derived units are used to describe derived quantities.

2) They can be expressed in terms of fundamental units.

3) Examples: Newton, Joule, Hertz, Pascal etc.

Ksenya-84 [330]3 years ago

8 0

Answer:

3diferences

Explanation:

fundamental are independent but derived are dependent

there are 7fundamental units but there are many derived units from fundamental.

meter, second, kilogram, etc are examples of fundamental but m/s^2, newton, joule, etc are derived units

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Hello!

blondinia [14]

Answer:

$[CO]=[Cl_2]=0.01436M$

$[COCl_2]=0.00064M$

Explanation:

Hello there!

In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:

$K=\frac{[CO][Cl_2]}{[COCl_2]}$

Which can be written in terms of x, according to the ICE table:

$0.32=\frac{x^2}{0.015M-x}$

Thus, we solve for x to obtain that it has a value of 0.01436 M and therefore, the concentrations at equilibrium turn out to be:

$[CO]=[Cl_2]=0.01436M$

$[COCl_2]=0.015M-0.01436M=0.00064M$

Regards!

5 0

2 years ago

using the soubility curve what is the solubilityof nh4cl in 10 mL of water at a temperature of 60 degrees Celsius

lukranit [14]

Answer:

Please, see attached two figures:

The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.

The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.

Answer: 5.5g

Explanation:

The red arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the solubility of NH₄Cl.

From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.

Assuming density 1.0 g/mol for water, 10 mL of water is:

$10mL\times 1.0g/mL=10g$

Thus, the solutibily is:

$10gWater\times 55gNH_4Cl/100gWater=5.5gNH_4Cl$

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goldenfox [79]

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andrew11 [14]

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3 point different between fundamental units and derived units​

3 point different between fundamental units and derived units