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zmey [24]
4 years ago
9

PLEASE HELP ME!!!! WILL MARK BRAINLIEST

Mathematics
1 answer:
Otrada [13]4 years ago
4 0

Answer:

h = 6

Step-by-step explanation:

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Answer this questions for 40 points! :) it is attached.
telo118 [61]
Im so confused by this question but my only guess would be that since a coin is a 1/2 chance getting it heads twice is 1/2 * 1/2 which is 1/4 so the person who best they can get 2 heads in a row pays 1/4 of the bet being 5 dollars because 1/4 of 20 is 5 and the person who bets that they can't get two heads pays 15 dollars because that is 3/4 of the bet

tldr: 1/4 chance to get heads pays 1/4 of bet 5$
3/4 chance not to get heads pays 3/4 of bet 15$
5 0
3 years ago
Read 2 more answers
The doubling period of a bacterial population is 20 20 minutes. At time t = 100 t=100 minutes, the bacterial population was 9000
Nuetrik [128]

Answer:

The initial population was 2810

The bacterial population after 5 hours will be 92335548

Step-by-step explanation:

The bacterial population growth formula is:

P = P_0 \times e^{rt}

where P is the population after time t, P_0 is the starting population, i.e. when t = 0, r is the rate of growth in % and t is time in hours

Data: The doubling period of a bacterial population is 20 minutes (1/3 hour). Replacing this information in the formula we get:

2 P_0 = P_0 \times e^{r 1/3}

2 = e^{r \; 1/3}

ln 2 = r \; 1/3

ln 2 \times 3 = r

2.08 \% = r

Data: At time t = 100 minutes (5/3 hours), the bacterial population was 90000. Replacing this information in the formula we get:

90000 = P_0 \times e^{2.08 \; 5/3}

\frac{9000}{e^{2.08 \; 5/3}} = P_0

2810 = P_0

Data: the initial population got above and t = 5 hours. Replacing this information in the formula we get:

P = 2810 \times e^{2.08 \; 5}

P = 92335548

3 0
3 years ago
ILL BRAINLIEST YOU IF YOU PLEASE HELP ME
Eddi Din [679]
1 < x < 5

Left side is 1 and right is 5
5 0
3 years ago
Help me to answer this question pl​s
attashe74 [19]

Problem 1

Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.

Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.

With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.

Refer to the diagram below.

=====================================================

Problem 2

I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.

In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.

8 0
2 years ago
Solve for the width in the formula for the area of a rectangle.
madam [21]
A = L * W
A / L = W <==

when A = 42 and W = 16.8
A / L = W
42/16.8 = W
2.5 = W <=== width = 2.5 inches
4 0
3 years ago
Read 2 more answers
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