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anyanavicka [17]
3 years ago
8

Find p(rolling 1 or 5) with one number cube

Mathematics
2 answers:
zhenek [66]3 years ago
6 0
P(rolling a 5) = 1/6
P(rolling a 1) = 1/6
P(rolling a 1 or a 5) = (1/6 ) + (1/6) = 1/3
The answer is 1/3
loris [4]3 years ago
4 0
<h2>Answer:</h2>

                    P(rolling 1 or 5)=1/3

<h2>Step-by-step explanation:</h2>

Let A represents the event of rolling a 1 on a number cube.

and B represents the event of rolling a 5 on a number cube.

Now we know that both the event A and B are independent.

Hence, we have:

P(A∩B)=0

Now, we are asked to find:  P(A∪B)

P(A∪B)=P(A)+P(B)-P(A∩B)

Hence, we have:

P(A∪B)=P(A)+P(B)

P(A)=1/6

( Since the outcomes on a number cube are: {1,2,3,4,5,6} )

and

P(B)=1/6

P(A∪B)=1/6+1/6

i.e.

P(A∪B)=2/6

i.e.

P(A∪B)=1/3

                Hence, the answer is: 1/3

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