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krok68 [10]
4 years ago
15

In a commercial chemical cold pack, an inner pouch containing water is broken and the water is allowed to mix with a sample of s

olid ammonium nitrate. The signs of the values for ΔH and ΔS for the dissociation reaction must be, respectivelyPositive, negativePositive, positiveNegative, positiveNegative, negative
Chemistry
1 answer:
yulyashka [42]4 years ago
5 0

Answer: Positive, positive

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from  an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

\Delta S is positive when randomness increases and \Delta S is negative when randomness decreases.

Exothermic reactions are defined as the reactions in which energy is released in the form of heat and \Delta H for the reaction comes out to be negative.

Endothermic reactions are defined as the reactions in which energy is absorbed in the form of heat and \Delta H for the reaction comes out to be positive.

For a cold pack, the energy has to be absorbed for the dissolution of ammonium nitrate in water so that the surroundings feel cold.Thus as energy is absorbed, \Delta H for the reaction comes out to be positive.

The solid form of ammonium nitrate is getting converted to ions and thus entropy increases and thus \Delta S for the reaction comes out to be positive.

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  • ΔH°r = Σ Eb broken - Σ Eb formed
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∴ ΔH°r = - 384 KJ/mol

∴ Br2 Eb = 193 KJ/mol

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⇒ Σ Eb broken = (1/2)(Br-Br) + (3/2)(F-F)

⇒ Σ Eb broken =  (1/2)(193 KJ/mol) + (3/2)(154 KJ/mol) = 327.5 KJ/mol

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⇒ Eb (Br-F) = 327.5 KJ/mol - ( - 384 KJ/mol )

⇒ Eb Br-F = 327.5 KJ/mol + 384 KJ/mol = 711.5 KJ/mol ≅ 712 KJ/mol

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