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just olya [345]
3 years ago
5

When solutions containing silver ions and chloride ions are mixed, silver chloride precipitates: Ag+(aq)+Cl−(aq)→AgCl(s)ΔH=−65.5

kJ. Calculate ΔH for formation of 0.490mol of AgCl by this reaction.
Chemistry
2 answers:
KATRIN_1 [288]3 years ago
5 0
<span>Arrhenius acid is acid which gives the H+ and arhenius base is one which donates the -OH group thats why it can identify</span>
laiz [17]3 years ago
4 0

Answer:

The ΔH for the formation of 0.490 mol of AgCl is - 32.095 kJ.

Explanation:

Ag⁺(aq)+Cl⁻(aq)→ AgCl(s) ΔH=−65.5kJ

We need to consider that the value of ΔH given is for each mol of AgCl formed.

1 mol AgCl ________________ - 65.5 kJ

0.490 mol AgCl ____________      x

x = - 32.095 kJ

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PLZ ANSWER QUICKLY! The electronegativity values of carbon, hydrogen, and nitrogen are compared in the table. Comparison of Elec
andriy [413]

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c. CH4 < NH3 because the NH bond is more polar than the CH bond.

Explanation:

Actually, the electronegativity difference between carbon and hydrogen is just about 0.4. This meager difference in electronegativity corresponds to a nonpolar bond between the two atoms.

However, the electronegativity difference between nitrogen and hydrogen is about 0.9. This larger electronegativity difference corresponds to the existence of a polar covalent bond between the two atoms.

Hence the N-H bond is significantly polar unlike the C-H bond. This implies that CH4 molecules are only held together by weak dispersion forces while NH3 molecules are held together by stronger dipole-dipole interactions and hydrogen bonds.

8 0
2 years ago
How much potassium chloride is needed to make 0.500 m solution with 1.50 L of water?
Andrew [12]

Answer:

55.9 g KCl.

Explanation:

Hello there!

In this case, according to the definition of molality for the 0.500-molar solution, we need to divide the moles of solute (potassium chloride) over the kilograms of solvent as shown below:

m=\frac{mol}{kilograms}

Thus, solving for the moles of solute, we obtain:

mol=m*kilograms

Since the density of water is 1 kg/L, we obtain the following moles:

mol=0.500mol/kg*1.50kg\\\\mol=0.75mol

Next, since the molar mass of KCl is 74.5513 g/mol, the mass would be:

0.75mol*\frac{74.5513g}{1mol}\\\\55.9g \ KCl

Regards!

4 0
3 years ago
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