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Nimfa-mama [501]
3 years ago
5

Power can be define as what

Physics
2 answers:
Jobisdone [24]3 years ago
4 0

An exponent

For example the power in 5^{2} is the 2. It is how many times the 5 is multiplying itself. In this case 5 would multiply itself 2 times.

So... not 5 x 2, but 5 x 5

I am Lyosha [343]3 years ago
3 0
<h2>Answer</h2>

It is the rate of doing work

<h2>Explanation</h2>

Power can be defined as the ability to influence the behavior of others and resist unwanted influence in return.

In physics, power is rate of doing work, or it’s the amount of energy transferred per unit time. Power is a scalar quantity mean a specific direction is not required for it.

Being the rate of work, the equation for power can be written:

Power = Work/Time

Work = F * d

For example

You are running upstair, you are applying force to cover some distance in specific time

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4 0
2 years ago
How much force is needed to accelerate a 1000-kg car at a rate of 3 m/s squared
Burka [1]

Answer:

3000 newton force is required

Explanation:

F = ma

F= 1000 kgs x 3 m/s^ 2

F=3000(kgs x m/s^2)

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8 0
3 years ago
what is the acceleration of a car that slows down from 60m/s to 40 m/s during a period of 10 seconds?
algol [13]

The acceleration of the car is stated as -2 m/s², while the deceleration of the car is termed as 2 m/s².

Answer:

Explanation:

Acceleration exerted by any object in order of decrease in the speed is termed as deceleration. In other words , negative acceleration or acceleration acting in opposite direction to stop the motion of any object is termed as deceleration. The magnitude of acceleration and deceleration is same only the direction is completely opposite to each other. So the negative sign will be obtained for acceleration value of any object whose velocity slows down from initial velocity.

Here , the initial velocity was 60 m/s and the final velocity is slowed down to 40 m/s in time 10 s.

So acceleration = (Final velocity - Initial velocty)/Time

Acceleration = (40-60)/10 = -20/10 = -2 m/s².

Thus, the acceleration of the car is stated as -2 m/s², while the deceleration of the car is termed as 2 m/s².

5 0
3 years ago
A wheel of radius 25cm has eight spokes. It is mounted on a fixed axle and is rotating at a constant angular speed w. You shoot
spayn [35]

Explanation:

We will assume that the rim of the wheel is also very thin, like the spokes. The distance <em>s</em><em> </em><em> </em>between the spokes along the rim is

s = \frac{1}{8}C = \frac{1}{8}(2\pi)(0.25\:\text{m}) = 0.196\:\text{m}

The 20-cm arrow, traveling at 6 m/s, will travel its length in

t = \dfrac{0.2\:\text{m}}{6\:\text{m/s}} = \dfrac{1}{30}\:\text{s}

The fastest speed that the wheel can spin without clipping the arrow is

v = \dfrac{s}{t} = \dfrac{0.196\:\text{m}}{\left(\dfrac{1}{30\:\text{s}}\right)} = 5.9\:\text{m/s}

The angular velocity \omega of the wheel is given by

\omega = \dfrac{v}{r} = \dfrac{5.9\:\text{m/s}}{0.25\:\text{m}} = 23.6\:\text{rad/s}

In terms of rev/s, we can convert the answer above as follows:

23.6\:\dfrac{\text{rad}}{\text{s}}×\dfrac{1\:\text{rev}}{2\pi\:\text{rad}} = 3.8\:\text{rev/s}

As you probably noticed, I did the calculations based on the assumption that I'm aiming for the edge of the wheel because this is the part of the wheel where a point travels a longer linear distance compared to ones closer to the axle, thus giving the arrow a better chance to pass through the wheel without getting clipped by the spokes. If you aim closer to the axle, then the wheel needs to spin slower to allow the arrow to get through without hitting the spokes.

3 0
3 years ago
10) Allen was curious about dog interaction at the dog park. He wondered if big dogs liked to play with big dogs and if little d
GalinKa [24]

Answer: B) hypothesis

Explanation:

8 0
3 years ago
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