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Harman [31]
3 years ago
14

When determining an element's identity, what is the most important subatomic part to examine?

Chemistry
1 answer:
Ket [755]3 years ago
5 0
D protons. <span>the identity of an element is determined by the total number of protons present in the nucleus of an atom contained in that partial element.
._.</span>
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First person with the right answer gets brainliest thanks (btw the numbers on the right are the answers choose the right one)
kap26 [50]
Molar mass of FE2O3=2(55.85)+3(16)=159.7

2.56g*1mol/159.7*2mol/1mol*55.85g/1mol=1.79g
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3 years ago
PLEASE HELP 50 POINTS A really colorful reaction is the synthesis reaction of aluminum and iodine, often called the “Purple Haze
marysya [2.9K]

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3 years ago
. What mass of ammonium chloride must be added to 250. mL of water to give a solution with pH
Eduardwww [97]

The mass of ammonium chloride that must be added is : ( A ) 4.7 g

<u>Given data :</u>

Volume of water ( V )  = 250 mL = 0.25 L

pH of solution = 4.85

Kb = 1.8 * 10⁻⁵

Kw = 10⁻¹⁴

Given that the dissolution of NH₄Cl gives NH₄⁺⁺ and Cl⁻ ions the equation is written as :

NH₄CI  +  H₂O  ⇄  NH₃ + H₃O⁺

where conc of H₃O⁺

[ H₃O⁺ ] = \sqrt{Ka.C}   and Ka = Kw / Kb

∴ Ka = 5.56 * 10⁻¹⁰

Next step : Determine the concentration of H₃O⁺  in the solution

pH = - log [ H₃O⁺ ] = 4.85

∴ [ H₃O⁺ ] in the solution = 1.14125 * 10⁻⁵

Next step : Determine the concentration of NH₄CI in the solution

C = [ H₃O⁺ ]² / Ka

  = ( 1.14125 * 10⁻⁵ )² /  5.56 * 10⁻¹⁰

  = 0.359 mol / L

Determine the number of moles of NH₄CI in the solution

n = C . V

  = 0.359 mol / L  * 0.25 L =  0.08979 mole

Final step : determine the mass of ammonium chloride that must be added to 250 mL

mass = n * molar mass

         = 0.08979 * 53.5 g/mol

         = 4.80 g  ≈ 4.7 grams

Therefore we can conclude that the mass of ammonium chloride that must be added is 4.7 g

Learn more about ammonium chloride : brainly.com/question/13050932

8 0
2 years ago
An unknown compound contains only carbon, hydrogen, and oxygen (CxHyOz). Combustion of 2.50g of this compound produced 3.67g of
REY [17]
The solution to the problem is as follows:

 <span>a) 

C + O2 = CO2 

Molar mass CO2 = 44 g/mol 

3.67 g CO2 * 1 mol / 44 g = 

=0.0834 mol CO2 = 0.0834 mol C 

I hope my answer has come to your help. God bless and have a nice day ahead!
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4 0
3 years ago
Explain what the name scandium lll oxide means in terms of electrons lost and gained and identify the correct formula
andre [41]
Scandium lost 3 electrons and gave them to oxygen the formula would be Sc2O3
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3 years ago
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