All categories

3 years ago

What speeds up a chemical reaction

Chemistry

1 answer:

storchak [24]3 years ago

5 0

Catalyst can speed up chemical reaction without being used up or involved in thr reaction..

You might be interested in

What two dose the transfer of light energy require

IrinaK [193]

Answer:

Magnetic fields and Electric fields

Explanation:

3 0

2 years ago

Question 7

chubhunter [2.5K]

This answer is D or c

5 0

2 years ago

If 4.0 g of helium gas occupies a volume of 22.4 L at 0 o C and a pressure of 1.0 atm, what volume does 3.0 g of He occupy under

WINSTONCH [101]

Answer:

the volume occupied by 3.0 g of the gas is 16.8 L.

Explanation:

Given;

initial reacting mass of the helium gas, m₁ = 4.0 g

volume occupied by the helium gas, V = 22.4 L

pressure of the gas, P = 1 .0 atm

temperature of the gas, T = 0⁰C = 273 K

atomic mass of helium gas, M = 4.0 g/mol

initial number of moles of the gas is calculated as follows;

$n_1 = \frac{m_1}{M} \\\\n_1 = \frac{4}{4} = 1$

The number of moles of the gas when the reacting mass is 3.0 g;

m₂ = 3.0 g

$n_2 = \frac{m_2}{M} \\\\n_2 = \frac{3}{4} \\\\n_2 = 0.75 \ mol$

The volume of the gas at 0.75 mol is determined using ideal gas law;

PV = nRT

$PV = nRT\\\\\frac{V}{n} = \frac{RT}{P} \\\\since, \ \frac{RT}{P} \ is \ constant,\ then;\\\frac{V_1}{n_1} = \frac{V_2}{n_2} \\\\V_2 = \frac{V_1n_2}{n_1} \\\\V_2 = \frac{22.4 \times 0.75}{1} \\\\V_2 = 16.8 \ L$

Therefore, the volume occupied by 3.0 g of the gas is 16.8 L.

4 0

3 years ago

A chemical reaction in which two or more substances undergo a chemical union to form a more complex substance is a _______ react

Georgia [21]

I believe the correct answer is B. Combination.

7 0

3 years ago

Read 2 more answers

What is the final concentration if 50.0 ml of a 2.00 m solution are diluted to 500.0 ml??

laila [671]

In order to calculate the final concentration of a dilution, it is important to memorise and remember the following equation:

C1V1/C2V2
Where:
C1 = Initial concentration
V1 = Initial volume
C2 = Final concentration
V2 = Final volume

We are given three of the four, and we are asked to calculate the final concentration in moles, so we may substitute these given values into our equation as follows:

C1V1 = C2V2
(2.00m)(50.0 mL) = (C2)(500mL)
100 = C2(500mL)
C2 = 0.2 m

In the final step, we simply divide 100 by 500 to get our final concentration value.

4 0

3 years ago