Answer:
The molar mass is the mass of a given chemical element or chemical compound (g) divided by the amount of substance(mol) .
Explanation:
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K value of water is 1x 10^-14
Answer:
c) +2 to 0
Explanation:
SO4 has a charge of -2, so the Cu attached to that has to be a +2 since the polyatomic molecule has no overall charge
Cu(s) is a solid metal and they have no charge, therefore it is zero
Copper undergoes Oxidation (gain of electrons)
Explanation:
The scientific notation:

where
and k is integer.
We have the example:

You can write the numbers in a "normal" form:

Make the sum:

And next write it in the scientific notation:

<h3>Other method:</h3>
You can add numbers in scientific notation if the power of tens in both number is the same.
Therefore you must convert the first number:

Now, you can make the sum:

The definition of a common ion as it applies to Le Chatelier's principle is an ion that is present in an equilibrium system and a compound added to the system. This is the case since in Le Chatelier's principle, it is based on an equilibrium system and where the reaction shifts to the left or to the right; towards the products or the reactants side.