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3 years ago

How many orbitals are in the n=3 level

2 answers:

7 0

The third shell has 3 subshells: the subshell, which has 1 orbital with 2 electrons, the subshell, which has 3 orbitals with 6 electrons, and the subshell, which has 5 orbitals with 10 electrons, for a total of 9 orbitals and 18 electrons.

loris [4]3 years ago

5 0

I The third shell has 3 subshells: the subshell, which has 1 orbital with 2 electrons, the subshell, which has 3 orbitals with 6 electrons, and the subshell, which has 5 orbitals with 10 electrons, for a total of 9 orbitals and 18 electrons.

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Nitroglycerin is a dangerous powerful explosive that violently decomposes when it is shaken or dropped. The Swedish chemist Alfr

pshichka [43]

Answer:

1. 2 C₃H₅N₃O₉(l) ⇒ 3 N₂(g) + 1/2 O₂(g) + 5 H₂O(g) + 6 CO₂(g)

2. 146 g of nitroglycerin.

Explanation:

1. Write a balanced chemical equation, including physical state symbols, for the decomposition of liquid nitroglycerin ( C₃H₅N₃O₉) into gaseous dinitrogen, gaseous dioxygen, gaseous water and gaseous carbon dioxide.

The equation is:

C₃H₅N₃O₉(l) ⇒ N₂(g) + O₂(g) + H₂O(g) + CO₂(g)

Since atomicities in nitroglycerin are odd, it is easier to balance this equation by multiplying this compound by 2. The balanced equation is:

2 C₃H₅N₃O₉(l) ⇒ 3 N₂(g) + 1/2 O₂(g) + 5 H₂O(g) + 6 CO₂(g)

2. Suppose 41.0L of carbon dioxide gas are produced by this reaction, at a temperature of −14.0°C and pressure of exactly 1 atm. Calculate the mass of nitroglycerin that must have reacted.

First, we have to find the moles of CO₂ using the ideal gas equation.

P.V = n . R . T

where,

P is the pressure

V is the volume

n is the number of moles

R is the ideal gas constant (0.08206atm.L/mol.K)

T is the absolute temperature (-14.0 °C + 273.15 = 259.2 K)

$P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{1atm . 41.0L}{(0.08206atm.L/mol.K).259.2K} =1.93mol$

According to the balanced equation, 6 moles of CO₂ are formed when 2 moles of C₃H₅N₃O₉ react. And the molar mass of nitroglycerin is 227 g/mol. Then, for 1.93 moles of CO₂:

$1.93mol(CO_{2}).\frac{2mol(nitroglycerin)}{6mol(CO_{2})} .\frac{227g(nitroglycerin)}{1mol(nitroglycerin)} =146g(nitroglycerin)$

8 0

4 years ago

Please help me with number 5

mrs_skeptik [129]

Fluorine - 18.998 u
chromium - 51.996 u
tellurium - 127.6 u
dysprosium - 162.5 u

6 0

4 years ago

What evidence did Alfred Wagner have to support his idea of continental drift

Novosadov [1.4K]

Alfred Wagner's evidence began at the simplest form that the continents appeared to fit together like pieces to a puzzle. It wasn't only that though. The evidence showed that the same rocks and fossils existed on separate continents - the same continents that if pieced together would be connected.

8 0

4 years ago

I need help with these 2 questions below:

uysha [10]

8 idk. ......but.... 9 it leaves evidence and a mess

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3 years ago

PLEASE HELP FAST IM ABOUT TO FAIL PLEASE HELP PLEASE HELP FAST HELP HELP THIS IS DESPRATE

MariettaO [177]

1. 0.240 liters of water would be needed to dissolve 21.6 g of lithium nitrate to make a 1.3 M (molar) solution.

2. 2.9 M is the molarity of a solution made of 215.1 g of HCl is dissolved to make 2.0 L of solution.

3.83.3 ml of concentrated 18 M H2SO4 is needed to prepare 250.0 mL of a 6.0 M solution.

4. 135 ml of stock HBr will be required to dilute the solution.

5. 150 ml of water should be added to 50.0 mL of 12 M hydrochloric acid to make a 4.0 M solution

6. The pH of the resulting solution is 13.89

Explanation:

The formula used in solving the problems is

number of moles= $\frac{mass}{atomic mass of one mole}$ 1st equation

molarity = $\frac{number of moles}{volume}$ 2nd equation

Dilution formula

M1V1 = M2V2 3rd equation

1. Data given

mass of Lithium nitrate = 21.6 grams

atomic mass of on emole lithium nitrate = 68.946 gram/mole

Molarity is given as 1.3 M

VOLUME=?

Calculate the number of moles using equation 1

n = $\frac{21.6}{68.946}$

= 0.313 moles of lithium nitrate.

volume is calculated by applying equation 2.

volume = $\frac{0.313}{1.3}$

= 0.240 litres of water will be used.

2. Data given:

mass of HCl = 215.1 gram

atomic mass of HCl = 36.46 gram/mole

volume = 2 litres

molarity = ?

using equation 1 number of moles calculated

number of moles = $\frac{215.1}{36.46}$

number of moles of HCl = 5.899 moles

molarity is calculated by using equation 2

M = $\frac{5.899}{2}$

= 2.9 M is the molarity of the solution of 2 litre HCl.

3. data given:

molarity of H2SO4 = 18 M

Solution to be made 250 ml of 6 M

USING EQUATION 3

18 x V1= 250 x 6

V1 = 83.3 ml of concentrated 18 M H2SO4 will be required.

4. data given:

M1= 10M, V1 =?, M2= 3 ,V2= 450 ml

applying the equation 3

10 x VI = 3x 450

V1 = 135 ml of stock HBr will be required.

5. Data given:

V1 = 50 ml

M1= 12 M

V2=?

M2= 4

applying the equation 3

50 x 12 = 4 x v2

V2 = 150 ml.

6. data given:

HCl + NaOH ⇒ NaCl + H20

molarity of NaOH = 0.525 M

volume of NaOH = 25 ml

molarity of acid HCl= 75 ml

volume of HCl = 0.335 ml

pH=?

Number of moles of NaOH and HCl is calculated by using equation 1 and converting volume in litres

moles of NaOH = 0.0131

moles of HCl= 0.025 moles

The ratio of moles is 1:1 . To find the unreacted moles of acid and base which does not participated in neutralization so the difference of number of moles of acid minus number of moles of base is taken.

difference of moles = 0.0119 moles ( NaOH moles is more)

Molarity can be calculated by using equation 1 in (25 +75 ml) litre of solution

molarity = $\frac{0.0119}{0.1}$

= 0.11 M (pOH Concentration)

14 = pH + pOH

pH = 14 - 0.11

pH = 13.89

3 0

3 years ago