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3 years ago

The weight of any object due to the downward force of what?

Physics

2 answers:

melomori [17]3 years ago

4 0

Isn't it "gravity" this would makes sense because grvaity difines weight

NARA [144]3 years ago

3 0

The "weight" of any object IS the force of gravity between the object and the Earth.

The force is always directed "down", because it's always directed toward the center of the Earth, and we call that direction "down" even though it's a different direction in every place.

You might be interested in

The kicker now kicks the ball with the same speed as in the number of 4,but at 60.0°from the horizontal or 30.0° from the vertic

Shkiper50 [21]

Answer:

i) 0.7

ii) 1.39

iii) 0.6

Next time, when compiling a Physics question, ensure you put the unit of each measurement.

Explanation:

i) T = time of flight = $\frac{2uSin(A)}{g}$

where u = speed = 4, A = 60 and g = acceleration due to gravity = 10 (It is a constant);

Subsituting the values, we have: T = $\frac{2(4)Sin(60)}{10}$ = 0.7

ii) distance travel = Range = R = $\frac{u^{2}Sin(2A) }{g}$

where u = speed = 4, A = 60 and g = acceleration due to gravity = 10 (It is a constant);

Subsituting values, we have: R = $\frac{4^{2}Sin(2*60) }{10}$ = 1.39

iii) Maximum Height = H = $\frac{u^{2}(Sin(A))^{2} }{2g}$

where u = speed = 4, A = 60 and g = acceleration due to gravity = 10 (It is a constant);

Subsituting values, we have: $\frac{4^{2}(Sin60)^{2} }{2*10}$ = 0.6

4 0

3 years ago

A spectroscope prism separates the white light from a star into a very wide spectrum. When widely spread, black lines appear in

topjm [15]

Answer:

C. It helps scientists detect dark matter.

Explanation:

I got a 100% on my test. hope it help and I hope your having an awesome day :)

5 0

3 years ago

Read 2 more answers

A jogger hears a car alarm and decides to investigate. While running toward the car, she hears an alarm frequency of 872.10 Hz.

Nata [24]

Answer:

v = 4.18 m/s

Explanation:

given,

frequency of the alarm = 872.10 Hz

after passing car frequency she hear = 851.10 Hz

Speed of sound = 343 m/s

speed of the jogger = ?

speed of the

$v_f = \dfrac{872.10-851.10}{2}$

$v_f =10.5\ Hz$

v_o = 872.1 - 10.5

$V_0 = 861.6\ Hz$

The speed of jogger

$v = \dfrac{v_1 \times 343}{v_0}-343$

$v = \dfrac{872.1 \times 343}{861.6}-343$

v = 4.18 m/s

5 0

3 years ago

A circular test track for cars has a circumference of 3.5 kmkm . A car travels around the track from the southernmost point to t

elixir [45]

Answer:

(A) Distance will be equal to 1.75 km

(B) Displacement will be equal to 1.114 km

Explanation:

We have given circumference of the circular track = 3.5 km

Circumference is given by $2\pi r=3.5$

r = 0.557 km

(a) It is given that car travels from southernmost point to the northernmost point.

For this car have to travel the distance equal to semi perimeter of the circular track

So distance will be equal to $=\frac{3.5}{2}=1.75km$

(b) If car go along the diameter of the circular track then it will also go from southernmost point to the northernmost point. and it will be equal to diameter of the track

So displacement will be equal to d = 2×0.557 = 1.114 m

8 0

3 years ago

inysia [295]

Hello and Good Morning/Afternoon:

Original Question: C₂H₅OH + __O₂ → __CO₂ + __ H₂O

To balance this equation:

⇒ must ensure that there is an equal number of elements on both sides of the equation at all times

Let's start balancing:

On the left side of the equation, there are 2 carbon molecule

⇒ but only so far one on the right side

C₂H₅OH + __O₂ → 2CO₂ + __ H₂O

On the left side of the equation, there are 6 hydrogen molecules

⇒ but only so far two on the right side

C₂H₅OH + __O₂ → 2CO₂ + 3H₂O

On the right side of the equation, there are 7 oxygen molecules

⇒ but only so far three on the left side

C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O

Let's check and make sure we got the answer:

C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O

2 Carbon ⇔ 2 Carbon

6 Hydrogen ⇔ 6 Hydrogen

7 Oxygen ⇔ 7 oxygen

Thefore the coefficients in order are:

⇒ 1, 3, 2, 3

Answer: 1,3,2,3

Hope that helps!

#LearnwithBrainly

5 0

2 years ago