All categories

3 years ago

Which kind of good might not be bought when prices rise?

Physics

2 answers:

inessss [21]3 years ago

6 0

Answer:

<h2>Luxury.</h2>

Explanation:

Luxuries is the sector that suffers more when prices rise, because these goods are not a need to people, they are just leisure and extra things, like having the last smartphone, or having two cars.

IgorC [24]3 years ago

5 0

luxury goods might not be bought

You might be interested in

Will mark as BRAINLIEST....... The Displacement x of particle moving in one dimension under the action of constant force is rela

pentagon [3]

Explanation:

It is given that,

The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:

$x=4t^3+3t^2-5t+2$

Where,

x is in meters and t is in sec

We know that,

Velocity,

$v=\dfrac{dx}{dt}\\\\v=\dfrac{d(4t^3+3t^2-5t+2)}{dt}\\\\v=12t^2+6t-5$

(a) i. t = 2 s

$v=12(2)^2+6(2)-5=55\ m/s$

At t = 4 s

$v=12(4)^2+6(4)-5=211\ m/s$

(b) Acceleration,

$a=\dfrac{dv}{dt}\\\\a=\dfrac{d(12t^2+6t-5)}{dt}\\\\a=24t+6$

Pu t = 3 s in the above equation

So,

$a=24(3)+6\\\\a=78\ m/s^2$

Hence, this is the required solution.

3 0

3 years ago

A particle is projected with velocity v0 directly up a slope which makes an angle α with the horizontal. Assume frictionless mot

Nikolay [14]

Answer:

a)T total = 2*Voy/(g*sin( α ))

b)α = 0º , T total≅∞ (the particle, goes away horizontally indefinitely)

α = 90º, T total=2*Voy/g

Explanation:

Velocity in the Y axis:

Voy=Vo*sinα

Time to reach the maximal height :

Kinematics equation: Vfy=Voy-at

a=g*sinα ; g is gravity

if Vfy=0 ⇒ t=T ; time to reach the maximal height

so:

0=Voy-g*sin( α )*T

T=Voy/(g*sin( α ))

Time required to return to the starting point:

After the object reaches its maximum height, the object descends to the starting point, the time it descends is the same as the time it rises.

So T total= 2T = 2*Voy/(g*sin( α ))

α = 0º , sinα=0

The particle goes totally horizontal, goes away indefinitely

T total= 2*Voy/(g*sin( α )) ≅∞

α = 90º, sinα=1

T total=2*Voy/g

6 0

3 years ago

Suppose astronomers built a 150-meter telescope. how much greater would its light-collecting area be than that of the 10-meter k

Dennis_Churaev [7]

Almost all telescopes have a circular mirror. The area of a circle is proportional to $r^2$ where $r$ is the radius of the circle, the constant of proportionality being $4\pi$
$S =4\pi r^2$
Therefore the area of 150 meter telescope would be
$S_1/S_2=(r_1/r_2)^2 =(75/5)^2 =15^2=225$
times bigger than the area of the smaller (10 meter) telescope.

6 0

2 years ago

Can we see the back side of the moon from earth?

Olegator [25]

No. The moon always keeps the same side facing us. Its rotation and revolution periods are equal.

5 0

2 years ago

Read 2 more answers

If earth's mass were half its actual value but its radius stayed the same, the escape velocity of earth would be:________

siniylev [52]

If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be $V_e = \sqrt{\dfrac{GM}{r}}$ .

<h3>What is an escape velocity?</h3>

The ratio of the object's travel distance over a specific period of time is known as its velocity. As a vector quantity, the velocity requires both the magnitude and the direction. the slowest possible speed at which a body can break out of the gravitational pull of a certain planet or another object.

The formula to calculate the escape velocity of earth is given below:-

$V_e=\sqrt{\dfrac{2GM}{r}}$

Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-

$V_e=\sqrt{\dfrac{2GM}{r\times 2}}$

$V_e = \sqrt{\dfrac{GM}{r}}$ .

Therefore, If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be $V_e = \sqrt{\dfrac{GM}{r}}$ .

To know more about escape velocity follow

brainly.com/question/14042253

#SPJ4

8 0

1 year ago