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Natasha2012 [34]
3 years ago
13

Explain an amusement park you've ridden discuss the conversion of energy on that ride

Physics
1 answer:
nika2105 [10]3 years ago
6 0
Roller coaster...

going up... building the potential energy....

SCREAM... AND SCREAM... kinetic energy upon kinetic energy being used

rinse and repeat
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if the velocity of a car is halved the fc required to keeo it in a path of constant radius is multiplied/divided by?
damaskus [11]
I believe this is it
The centripetal force is given by
F = mv^2 / r
When v' = v/2,
F' = mv'^2/r = m(v/2)^2/r = mv^2/4r = F/4.
So the centripetal force is divided by 4.
7 0
3 years ago
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What is the momentum of a 750 kg car traveling at a velocity of 25 m/s north?
olga_2 [115]

Answer:

18750 kg-m/s

Explanation:

Momentum = mass x velocity 

3 0
3 years ago
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What’s the answer to question 12 please
matrenka [14]

Answer:

C) amplitude

Explanation:

"The amplitude is a measure of the strength or intensity of the wave. For example, when looking at a sound wave, the amplitude will measure the loudness of the sound. The energy of the wave also varies in direct proportion to the amplitude of the wave."-Ducksters

7 0
3 years ago
Atomic physicists usually ignore the effect of gravity within an atom. To see why, we may calculate and compare the magnitude of
STatiana [176]

Answer:

2.27\cdot 10^{49}

Explanation:

The gravitational force between the proton and the electron is given by

F_G=G\frac{m_p m_e}{r^2}

where

G is the gravitational constant

m_p is the proton mass

m_e is the electron mass

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

F_G=(6.67259\cdot 10^{-11} m^3 kg s^{-2})\frac{(1.67262\cdot 10^{-27}kg) (9.10939\cdot 10^{-31}kg)}{(3 m)^2}=1.13\cdot 10^{-68}N

The electrical force between the proton and the electron is given by

F_E=k\frac{q_p q_e}{r^2}

where

k is the Coulomb constant

q_p = q_e = q is the elementary charge (charge of the proton and of the electron)

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

F_E=(8.98755\cdot 10^9 Nm^2 C^{-2})\frac{(1.602\cdot 10^{-19}C)^2}{(3 m)^2}=2.56\cdot 10^{-19}N

So, the ratio of the electrical force to the gravitational force is

\frac{F_E}{F_G}=\frac{2.56\cdot 10^{-19} N}{1.13\cdot 10^{-68}N}=2.27\cdot 10^{49}

So, we see that the electrical force is much larger than the gravitational force.

5 0
3 years ago
A 22kg Accelerates at a rate of 2.3 m/s. What is the magnitude of the net force acting on the bike?
Tcecarenko [31]

magnitude of the net force = mass x acceleraton

                                             = 22 x 2.3

                                             =50.6 N

7 0
3 years ago
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