The total angles in a polygon is 180 (n -2) where n is the number of sides.
A traingle has 3 sides. using the formula 180 x (3-2) = 180
So
X + Y + Y = 180
X + 2Y = 180 ...eq1
A pentagon has 5 sides, using the formula
180 x (5-2) = 540.
All the Y adds up to 540.
10Y = 540
Y = 54.
Use Y = 54 and sub into eq1
X + 2(54) =180
X = 180 - 2(54)
X = 180 -108
X =72
So X is 72
and Y is 54
Answer:
2) x=-4 y=4 4) x=0 y=-4
Step-by-step explanation:
<em>2)</em> Step: Substitute x+8 for y in y=−4x−12:
y=−4x−12
x+8=−4x−12
x+8+4x=−4x−12+4x (Add 4x to both sides)
5x+8=−12
5x+8+−8=−12+−8 (Add -8 to both sides)
5x=−20
5x
/5 = −20
/5 (Divide both sides by 5)
x=−4
Step: Substitute −4 for x in y=x+8:
y=x+8
y=−4+8
y=4 (Simplify both sides of the equation)
Answer:
x=−4 and y=4
<em>4) </em>Step: Substitute 3x−4 for y in y=x−4:
y=x−4
3x−4=x−4
3x−4+−x=x−4+−x (Add -x to both sides)
2x−4=−4
2x−4+4=−4+4 (Add 4 to both sides)
2x=0
2x/2 = 0
/2 (Divide both sides by 2)
x=0
Step: Substitute 0 for x in y=3x−4:
y=3x−4
y=(3)(0)−4
y=−4 (Simplify both sides of the equation)
Answer:
x=0 and y=−4
Answer: 140
Oleg, Sasha, and Dima shared 600 toys. Sasha had twice as many toys as Oleg. Dima had 40 more toys than Oleg.
Let the number of toys Oleg has = x
Let the number of toys Sasha has = y
Let the number of toys Dima has = z
Sasha had twice as many toys as Oleg
So y = 2*x= 2x
Dima had 40 more toys than Oleg.
z = x + 40
Oleg, Sasha, and Dima shared 600 toys
x + y + z= 600
We know y=2x and z=x+40
Replace it for y and z
Subtract 40 on both sides
Divide by 4 on both sides
Oleg had 140 toys
Step-by-step explanation: