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irakobra [83]
4 years ago
6

5 physical properties of all matter

Chemistry
2 answers:
Alexus [3.1K]4 years ago
7 0

color

density

volume

mass

boiling point

melting point

natta225 [31]4 years ago
5 0
Color (intensive)
density (intensive)
volume (extensive)
mass (extensive)
boiling point (intensive): the temperature at which a substance boils.
melting point (intensive): the temperature at which a substance melts
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Which law was used to determine the relationship between the volume and the number of moles?​
lawyer [7]

Answer:

The Mole-Volume Relationship: Avogadro's Law. A plot of the effect of temperature on the volume of a gas at constant pressure shows that the volume of a gas is directly proportional to the number of moles of that gas. This is stated as Avogadro's law.

Explanation:

4 0
3 years ago
Which of the following is most likely to be covalent?<br> MgO <br> CO <br> CaO <br> BaO
Kisachek [45]

Answer:

CaO

Explanation:

CaO is the only compound that is a non-metal and a non-metal. The rest of the compounds are ionic, or metal and non-metal.

8 0
3 years ago
A certain element exists as two different isotopes. 65.0% of its atoms have a mass of 24 amu and 35.0% of its atoms have a mass
Sauron [17]

Answer:

24.7 amu

Explanation:

An isotope is when an element can have different number of neutrons but they have same number of protons.

In order to calculate the average atomic mass with the given information do the following operations:

First change de percentages to fractional numbers, divide by 100.

I like to make a table, to organize all data and I believe is easier to understand.

65/100 = 0.65

35/100 = 0.35

% fraction

65.0 0.65

35.0 0.35

total100.0 1

Now multiply each mass with their corresponding fraction

24 (0.65) = 15.6

26 (0.35) = 9.1

%    fraction uma uma

65.0 0.65 24 15.6

35.0 0.35 26 9.1

total100.0    1          24.7

Finally you add the resulting mass and the units will be in uma.

15.6+9.1 = 24.7

Therefore the average atomic mass of this element will be 24.7 uma.

Check the table in the document attached

Download xlsx
4 0
3 years ago
Lab activity - Law of Conservation of Mass with vinegar and baking soda.
lesya [120]

Answer: I BIG DUMB

Explanation:

7 0
3 years ago
In an organic structure, you can classify each of the carbons as follows: Primary carbon (1o) = carbon bonded to just 1 other ca
Alla [95]

The question is incomplete, complete question is :

In an organic structure, you can classify each of the carbons as follows: Primary carbon (1°) = carbon bonded to just 1 other carbon group Secondary carbon (2°) = carbon bonded to 2 other carbon groups Tertiary carbon (3°) = carbon bonded to 3 other carbon groups Quaternary carbon (4°) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?

Structure is given in an image?

Answer:

There are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.

Explanation:

Total numbers of carbon = 10

Number of primary carbons that is carbon joined to just single carbon atom = 6

Number of secondary carbons that is carbon joined to two carbon atoms = 1

Number of tertiary carbons that is carbon joined to three carbon atoms = 2

Number of quartenary carbons that is carbon joined to four carbon atoms = 1

So, there are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.

3 0
3 years ago
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