Water and sodium oxide have different properties because of their nature as explained below.
<h3><u>Explanation:</u></h3>
Sodium oxide is a oxide of metallic sodium, while water is an oxide of hydrogen. So sodium oxide is a metallic oxide, while water is a non metallic oxide. Sodium oxide is a basic oxide, while water is neutral. As state of matter is concerned, sodium oxide is solid in normal room temperature, while water is liquid in normal room temperature. Water is a polar covalent molecule with partial charges on oxygen, but sodium oxide is an ionic molecule.
So all these factors contribute to very different properties of both sodium oxide and water.
Answer:
84.259 kPa
Explanation:
We know that:
1 kPa is approximately equal to 7.5 mmHg
Therefore, to convert 632 mmHg to kPa, we will simply use cross multiplication as follows:
1 kPa .................> 7.5006 mmHg
?? kPa ................> 632 mmHg
632 mmHg = (632*1) / (7.5006) = 84.259 kPa
Hope this helps :)
The number of hydrogen atoms that are in 7.80 moles of ammonium sulfide are 3.756 x 10^25 atoms
<u>calculation</u>
Step 1: calculate the moles of H in (NH4)2S
since there are 8 atoms of H in (NH4)2S the moles of
H = 8 x7.80 = 62.4 mole
Step 2: use of Avogadro's law constant to determine the number of H atom
that is 1 mole = 6.02 x10^23 atoms
62.4 moles=? atoms
= [ 62.4 x 6.02 x10^23]/ 1 mole= 3.756 x10^25 atoms
I got on here because I don't understand the question but I did my best to answer because I noticed you asked 3 days ago. IF I'm right the answer is D. My diagram shows
A at -50 °C
B at 0 °C
C at 50 °C
D at 100 °C (gas to liquid or liquid to gas)
And E at 150 °C
So I hope I'm right because I'm answering the same question.
The correct answer is Bromine
Hope this helped:)