Answer:
a. Rate = k×[A]
b. k = 0.213s⁻¹
Explanation:
a. When you are studying the kinetics of a reaction such as:
A + B → Products.
General rate law must be like:
Rate = k×[A]ᵃ[B]ᵇ
You must make experiments change initial concentrations of A and B trying to find k, a and b parameters.
If you see experiments 1 and 3, concentration of A is doubled and the Rate of the reaction is doubled to. That means a = 1
Rate = k×[A]¹[B]ᵇ
In experiment 1 and to the concentration of B change from 1.50M to 2.50M but rate maintains the same. That is only possible if b = 0. (The kinetics of the reaction is indepent to [B]
Rate = k×[A][B]⁰
<h3>Rate = k×[A]</h3>
b. Replacing with values of experiment 1 (You can do the same with experiment 3 obtaining the same) k is:
Rate = k×[A]
0.320M/s = k×[1.50M]
<h3>k = 0.213s⁻¹</h3>
Answer:
The answer to your question is SO₂ + 3H₂ ⇒ H₂S + 2H₂O
Explanation:
Reaction
SO₂ + H₂ ⇒ H₂S + H₂O
Reactants Elements Products
1 Sulfur 1
2 Hydrogen 4
2 Oxygen 1
This reaction is unbalanced so we need to balance it.
SO₂ + 3H₂ ⇒ H₂S + 2H₂O
Reactants Elements Products
1 Sulfur 1
6 Hydrogen 6
2 Oxygen 2
Now, the reaction is balanced
Answer:
They are 1.204×10^24 atoms of hydrogen present in 18 grams of water. In order to calculate this,it is necessary to compute the number of hydrogen moles present in the sample.
