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coldgirl [10]
3 years ago
9

In this experiment, you will use a track and a toy car to explore the concept of movement. You will measure the time it takes th

e car to travel certain distances, and then complete some calculations. In the space below, write a scientific question that you will answer by doing this experiment.
Chemistry
2 answers:
Helga [31]3 years ago
8 0
<span>A scientific question is like a hypothesis. It's the question that you're trying to answer throughout the experiment. So, a scientific question in this case could be: If the car has bigger wheels, will it travel faster? This is something you can test in the experiment, by having different cars with different sized wheels. In this way, you can track how fast each car goes, and determine whether or not the wheel size increases speed, decreases speed, or has no effect on speed.</span>
Gemiola [76]3 years ago
4 0
<span>How does an object's position and velocity change as the object accelerates</span>
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Which is true about the pH values of a 1.0 M solution of HCl (a strong acid) and a 1.0 M solution of HC2H3O2 (a weak acid)?
Neko [114]

Answer:

C. pH values are different because the HC_2H_3O_2 solution partially ionizes and the HCl solution ionizes 100 percent.

Explanation:

Strong acids are the acids which completely ionizes in the solution while weak acids are the acids which ionizes partially in the solution. They exists in equilibrium in the solution with their respective ions.

Thus, strong acids furnish greater concentration of protons as compared to weak acid when same concentration of both types are taken.

<u>Also, pH is the negative of the logarithm  of the hydrogen ions. Thus, hydrogen ion concentration for both acids are different and thus pH will be different.</u>

4 0
3 years ago
Determine Z and V for steam at 250°C and 1800 kPa by the following: (a) The truncated virial equation [Eq. (3.38)] with the foll
makvit [3.9K]

Answer:

Explanation:

Given that:

the temperature T_1 = 250 °C= ( 250+ 273.15 ) K = 523.15 K

Pressure = 1800 kPa

a)

The truncated viral equation is expressed as:

\frac{PV}{RT} = 1 + \frac{B}{V} + \frac{C}{V^2}

where; B = - 152.5 \ cm^3 /mol   C = -5800 cm^6/mol^2

R = 8.314 × 10³ cm³ kPa. K⁻¹.mol⁻¹

Plugging all our values; we have

\frac{1800*V}{8.314*10^3*523.15} = 1+ \frac{-152.5}{V} + \frac{-5800}{V^2}

4.138*10^{-4}  \ V= 1+ \frac{-152.5}{V} + \frac{-5800}{V^2}

Multiplying through with V² ; we have

4.138*10^4  \ V ^3 = V^2 - 152.5 V - 5800 = 0

4.138*10^4  \ V ^3 - V^2 + 152.5 V + 5800 = 0

V = 2250.06  cm³ mol⁻¹

Z = \frac{PV}{RT}

Z = \frac{1800*2250.06}{8.314*10^3*523.15}

Z = 0.931

b) The truncated virial equation [Eq. (3.36)], with a value of B from the generalized Pitzer correlation [Eqs. (3.58)–(3.62)].

The generalized Pitzer correlation is :

T_c = 647.1 \ K \\ \\ P_c = 22055 \  kPa  \\ \\ \omega = 0.345

T__{\gamma}} = \frac{T}{T_c}

T__{\gamma}} = \frac{523.15}{647.1}

T__{\gamma}} = 0.808

P__{\gamma}} = \frac{P}{P_c}

P__{\gamma}} = \frac{1800}{22055}

P__{\gamma}} = 0.0816

B_o = 0.083 - \frac{0.422}{T__{\gamma}}^{1.6}}

B_o = 0.083 - \frac{0.422}{0.808^{1.6}}

B_o = 0.51

B_1 = 0.139 - \frac{0.172}{T__{\gamma}}^{ \ 4.2}}

B_1 = -0.282

The compressibility is calculated as:

Z = 1+ (B_o + \omega B_1 ) \frac{P__{\gamma}}{T__{\gamma}}

Z = 1+ (-0.51 +(0.345* - 0.282) ) \frac{0.0816}{0.808}

Z = 0.9386

V= \frac{ZRT}{P}

V= \frac{0.9386*8.314*10^3*523.15}{1800}

V = 2268.01 cm³ mol⁻¹

c) From the steam tables (App. E).

At T_1 = 523.15 \  K \ and  \ P = 1800 \ k Pa

V = 0.1249 m³/ kg

M (molecular weight) = 18.015 gm/mol

V  =  0.1249 × 10³ × 18.015

V = 2250.07 cm³/mol⁻¹

R = 729.77 J/kg.K

Z = \frac{PV}{RT}

Z = \frac{1800*10^3 *0.1249}{729.77*523.15}

Z = 0.588

3 0
3 years ago
Pregnant women are often cautioned against cleaning cat litter boxes. This is because Toxoplasma, an intestinal parasite of cats
Kryger [21]

Answer:

A communicable disease

Explanation:

Diseases that can be transferred are known as communicable diseases.

5 0
2 years ago
How many grams of water can be produce from the complete reaction of excess nitric acid and 33.2 mL of 0.245 M lithium hydroxide
Mariulka [41]

Mass of water produced : 0.146 g

<h3>Further explanation</h3>

Given

33.2 mL of 0.245 M lithium hydroxide

Required

mass of water

Solution

Reaction

HNO₃ (aq) + LiOH (aq) → H₂O (l) + LiNO₃ (aq)

mol LiOH :

= M x V

= 0.245 x 33.2 ml

= 8.134 mmol

From the equation, the mol ratio of HNO₃ : H₂O = 1 : 1, so mol H₂O = 8.134 mmol

mass H₂O :

= mol x MW

= 8.134 x 10⁻³ mol x 18 g/mol

= 0.146 g

3 0
3 years ago
How are silicate minerals different from nonsilicate minerals
tino4ka555 [31]

Answer: The main difference between silicate minerals and nonsilicate minerals is that silicate minerals are composed of silicate groups whereas Nonsilicate minerals have no silicate groups.

Explanation:

7 0
3 years ago
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