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coldgirl [10]
3 years ago
9

In this experiment, you will use a track and a toy car to explore the concept of movement. You will measure the time it takes th

e car to travel certain distances, and then complete some calculations. In the space below, write a scientific question that you will answer by doing this experiment.
Chemistry
2 answers:
Helga [31]3 years ago
8 0
<span>A scientific question is like a hypothesis. It's the question that you're trying to answer throughout the experiment. So, a scientific question in this case could be: If the car has bigger wheels, will it travel faster? This is something you can test in the experiment, by having different cars with different sized wheels. In this way, you can track how fast each car goes, and determine whether or not the wheel size increases speed, decreases speed, or has no effect on speed.</span>
Gemiola [76]3 years ago
4 0
<span>How does an object's position and velocity change as the object accelerates</span>
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Briefly describe how the apparatus work​
Bess [88]

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4 0
2 years ago
Read 2 more answers
A chemist titrates 130.0mL of a 0.4248 M lidocaine (C14H21NONH) solution with 0.4429 M HBr solution at 25 degree C . Calculate t
jeka57 [31]

Answer:

pH = 3.36

Explanation:

Lidocaine is a weak base to be titrated with the strong acid HBr, therefore at equivalence point we wil have the protonated lidocaine weak conjugate acid of lidocaine which will drive the pH.

Thus to solve the question we will need to calculate the concentration of this weak acid at equivalence point.

Molarity = mol /V ∴ mol = V x M

mol lidocaine = (130 mL/1000 mL/L) x 0.4248 mol/L = 0.0552 mol

The volume of 0.4429 M HBr required to neutralize this 0.0552 mol is

0.0552 mol x  (1L / 0.4429mol) = 0.125 L

Total volume at equivalence is  initial volume lidocaine + volume HBr added

0 .130 L +0.125 L = 0.255L

and the concentration of protonated lidocaine at the end of the titration will be

0.0552 mol / 0.255 L = 0.22M

Now to calculate the pH we setup our customary ICE table for  weak acids for the equilibria:

protonated lidocaine + H₂O   ⇆  lidocaine + H₃O⁺

                      protonated lidocaine          lidocaine        H₃O⁺

Initial(M)               0.22                                       0                  0

Change                   -x                                      +x                 +x

Equilibrium          0.22 - x                                  x                    x

We know for this equilibrium

Ka = [Lidocaine] [H₃O⁺] / [protonaded Lidocaine] =  x² / ( 0.22 - x )

The Ka can be calculated from the given pKb for lidocaine

Kb = antilog( - 7.94 ) = 1.15 x 10⁻⁸

Ka = Kw / Kb = 10⁻¹⁴ / 1.15 x 10⁻⁸  = 8.71 x 10⁻⁷

Since Ka is very small we can make the approximation 0.22  - x  ≈ 0.22

and solve for x. The pH  will then  be the negative log of this value.

8.71 x 10⁻⁷  = x² / 0.22 ⇒ x = √(/ 8.71 X 10⁻⁷ x 0.22) = 4.38 x 10⁻⁴

( Indeed our approximation checks since 4.38 x 10⁻⁴ is just 0.2 % of 0.22 )

pH = - log ( 4.4x 10⁻⁴) = 3.36

3 0
3 years ago
Which chemical symbols will complete the equation for this decomposition reaction?
kondaur [170]

Answer:

Decomposition of KI:

2KI → 2K + 2I

6 0
3 years ago
Read 2 more answers
How does a Camel prevent the loss of water from their body?​
Schach [20]

Camels lose less water through their urine and feces than many other mammals. Their kidneys concentrate water heavily, leading to salty urine. The intestines also reabsorb water from intestinal material as it is digested, so dry feces are produced.

7 0
2 years ago
NEED HELP WITH THIS CHEMISTRY QUESTION
denis-greek [22]

Answer:

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Explanation:

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