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My name is Ann [436]

3 years ago

14

A force of 185 n is needed to keep a small boat moving at 2.39 m/s. what is the power required to keep the boat moving at the st

eady speed?

1 answer:

mash [69]3 years ago

5 0

We know, P = F . ΔV

P = 185 * 2.39 = 442.15 watt

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When tuning a guitar, by comparing the frequency of a string that is struck against a standard sound source (of known frequency)

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Your grandmother enjoys creating pottery as a hobby. She uses a potter's wheel, which is a stone disk of radius R-0.520 m and ma

Lesechka [4]

Answer:

0.54454

104.00902 N

Explanation:

m = Mass of wheel = 100 kg

r = Radius = 0.52 m

t = Time taken = 6 seconds

$\omega_f$ = Final angular velocity

$\omega_i$ = Initial angular velocity

$\alpha$ = Angular acceleration

Mass of inertia is given by

$I=\dfrac{mr^2}{2}\\\Rightarrow I=\dfrac{100\times 0.52^2}{2}\\\Rightarrow I=13.52\ kgm^2$

Angular acceleration is given by

$\alpha=\dfrac{\tau}{I}\\\Rightarrow \alpha=\dfrac{\mu fr}{I}\\\Rightarrow \alpha=\dfrac{\mu 50\times 0.52}{13.52}$

Equation of rotational motion

$\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=\omega_i+\dfrac{\mu (-50)\times 0.52}{13.52}t\\\Rightarrow 0=60\times \dfrac{2\pi}{60}+\dfrac{\mu (-50)\times 0.52}{13.52}\times 6\\\Rightarrow 0=6.28318-11.53846\mu\\\Rightarrow \mu=\dfrac{6.28318}{11.53846}\\\Rightarrow \mu=0.54454$

The coefficient of friction is 0.54454

At r = 0.25 m

$\omega_f=\omega_i+\dfrac{0.54454 (-50)\times 0.52}{13.52}6\\\Rightarrow 0=60\times \dfrac{2\pi}{60}+\dfrac{0.54454 f\times 0.25}{13.52}6\\\Rightarrow 2\pi=0.06041f\\\Rightarrow f=\dfrac{2\pi}{0.06041}\\\Rightarrow f=104.00902\ N$

The force needed to stop the wheel is 104.00902 N

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3 years ago

Determine the volume of a cube whose width is 32.1 cm. Round your answer to the correct number significant figures.

Romashka [77]

The volume of a cube is given by:

$V=L^3$

where L is the measure of each side (which corresponds to its width, since all sides of a cube are equal).

Plugging the data of the problem, L=32.1 cm, inside the equation, we find the volume:

$V=L^3 =(32.1 cm)^3 =33076.2 cm^3$

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3 years ago

Wile E. Coyote stands on top of a 90-meter high cliff, looking down at the Roadrunner. If

Lina20 [59]

Answer:

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Explanation:

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