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Varvara68 [4.7K]

4 years ago

6

The portion of earth underneath the crust containing the asthenosphere and the mesosphere is the

1 answer:

Hatshy [7]4 years ago

6 0

Answer:

The portion of earth underneath the crust containing the asthenosphere and mesosphere is outer core and inner core .

Explanation:

The outer core of the earth is ball of very hot metals . Its temperature is hot enough to melt all metals into liquid state . This is mainly composed of the melted metals nickel and iron . This has got got temperature between 4000 degrees to 9000 degrees .

Inner core is underneath the outer core ,Here the pressure is too high and this makes the metals squeezed and not even able to move like liquid . They are forced to vibrate just like a solid . This has got a thickness of 800 miles . The pressure here is comparably 3,000,000 times the air pressure at sea level.

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Citrus2011 [14]

Answer:

$\theta = 66.7 degree$

Explanation:

since force is applied downwards at some angle with the horizontal

so here we will have

$F_n = mg + Fsin\theta$

now we know that the box will not move if applied force is balanced by frictional force on it

so we will have

$Fcos\theta = \mu F_n$

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so here we can say

$cos\theta - \mu sin\theta > 0$

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3 years ago

A parallel-plate vacuum capacitor has 8.38 J of energy stored in it. The separation between the plates is 2.30 mm. If the separa

Elanso [62]

Answer:

Explanation:

plate separation = 2.3 x 10⁻³ m

capacity C₁ = ε A / d

= ε A / 2.3 x 10⁻³

C₂ = ε A / 1.15 x 10⁻³

$\frac{C_2}{C_1}$ = $\frac{2.3}{1.15}$

a ) when charge remains constant

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q is charge and C is capacity

energy stored initially E₁= $\frac{q^2}{2C_1}$

energy stored finally E₂ = $\frac{q^2}{2C_2}$

$\frac{E_1}{E_2} = \frac{C_2}{C_1}$ = $\frac{2.3}{1.15}$

$E_2$ = $\frac{1.15}{2.3 } \times E_1$

= $\frac{1.15}{2.3 } \times 8.38$

= 4.19 J

b )

In this case potential diff remains constant

energy of capacitor = 1/2 C V²

energy is proportional to capacity as V is constant .

$\frac{E_2}{E_1} = \frac{C_2}{C_1}$

$\frac{E_2}{8.38} = \frac{2.3}{1.15}$

$E_2$ = 16.76 .

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