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Varvara68 [4.7K]
4 years ago
6

The portion of earth underneath the crust containing the asthenosphere and the mesosphere is the

Physics
1 answer:
Hatshy [7]4 years ago
6 0

Answer:

The portion of earth underneath the crust containing the asthenosphere  and mesosphere is outer core and inner core .

Explanation:

The outer core of the earth is ball of very hot metals . Its temperature is hot enough to melt all metals into liquid state . This is mainly composed of the melted metals nickel and iron . This has got got temperature between 4000 degrees to 9000 degrees .

Inner core is underneath the outer core ,Here the pressure is too high and this makes the metals squeezed and not even able to move like liquid . They are forced to vibrate just like a solid . This has got a thickness of 800 miles . The pressure here is comparably 3,000,000 times the air pressure at sea level.

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While moving in, a new homeowner is pushing a box across the floor at a constant velocity. The coefficient of kinetic friction b
Citrus2011 [14]

Answer:

\theta = 66.7 degree

Explanation:

since force is applied downwards at some angle with the horizontal

so here we will have

F_n = mg + Fsin\theta

now we know that the box will not move if applied force is balanced by frictional force on it

so we will have

Fcos\theta = \mu F_n

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F = \frac{\mu mg}{cos\theta - \mu sin\theta}

so here we can say

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3 years ago
A parallel-plate vacuum capacitor has 8.38 J of energy stored in it. The separation between the plates is 2.30 mm. If the separa
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Answer:

Explanation:

plate separation = 2.3 x 10⁻³ m

capacity C₁ = ε A / d

= ε A / 2.3 x 10⁻³

C₂ = ε A / 1.15 x 10⁻³

\frac{C_2}{C_1} = \frac{2.3}{1.15}

a ) when charge remains constant

energy = \frac{q^2}{2C}

q is charge and C is capacity

energy stored initially E₁= \frac{q^2}{2C_1}

energy stored finally E₂ = \frac{q^2}{2C_2}

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E_2 = \frac{1.15}{2.3 } \times E_1

= \frac{1.15}{2.3 } \times 8.38

= 4.19 J

b )

In this case potential diff remains constant

energy of capacitor = 1/2 C V²

energy is proportional to capacity as V is constant .

\frac{E_2}{E_1} = \frac{C_2}{C_1}

\frac{E_2}{8.38} = \frac{2.3}{1.15}

E_2 = 16.76 .

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If you pour different liquids into a graduated cylinder, which layer would be at the bottom?
klasskru [66]

the one that is more dense!

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