Answer:
b is the answer
Explanation:
tq friend b is the answer
Answer:
the density of mobile electrons in the material is 3.4716 × 10²⁵ m⁻³
Explanation:
Given the data in the question;
we make use of the following expression;
hall Voltage VH = IB / ned
where I = 2.25 A
B = 0.685 T
d = 0.107 mm = 0.107 × 10⁻³ m
e = 1.602×10⁻¹⁹ C
VH = 2.59 mV = 2.59 × 10⁻³ volt
n is the electron density
so from the form; VH = IB / ned
VHned = IB
n = IB / VHed
so we substitute
n = (2.25 × 0.685) / ( 2.59 × 10⁻³ × 1.602×10⁻¹⁹ × 0.107 × 10⁻³ )
n = 1.54125 / 4.4396226 × 10⁻²⁶
n = 3.4716 × 10²⁵ m⁻³
Therefore, the density of mobile electrons in the material is 3.4716 × 10²⁵ m⁻³
Explanation:
because the acceleration is negative, this indicates a deceleration (or slowing down) . Hence we can say that:
The car is decelerating (slowing down), i.e its velocity is decreasing, at a constant rate of 5m/s².
Answer:
10m/s
Explanation:
Using the law of conservation of momentums
M1u1+m2u2 = (m1+m2)v
Substitute.
4000(10)+1500(10) = (4000+1500)v
40,000+15,000 = 5,500v
55000 = 5500v
v = 55000/5500
v= 10m/s
Hence the velocity of the truck after Collision is 10m/s
