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MakcuM [25]
2 years ago
12

A dog goes for a walk in the neighborhood leaves home and take several displacements as follows. It first head

Physics
1 answer:
Korvikt [17]2 years ago
4 0

Answer:

sorry i couldn't answer your question I tried

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A person hears a siren as a fire truck approaches and passes by. The frequency varies from 480Hz on approach to 400Hz going away
alekssr [168]

Answer:

31.2 m/s

Explanation:

f_{app} = Frequency of approach = 480 Hz

f_{aw} = Frequency of going away = 400 Hz

V = Speed of sound in air = 343 m/s

v = Speed of truck

Frequency of approach is given as

f_{app} = \frac{Vf}{V - v}                           eq-1

Frequency of moving awayy is given as

f_{aw} = \frac{Vf}{V + v}                          eq-2

Dividing eq-1 by eq-2

\frac{f_{app}}{f_{aw}} = \frac{V + v}{V - v}

\frac{480}{400} = \frac{343 + v}{343 - v}

v = 31.2 m/s

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3 years ago
A physical change is a change to the physical properties of a substance. This type of change does
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False

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