A dog goes for a walk in the neighborhood leaves home and take several displacements as follows. It first head

When a block of ice at zero degrees Celsius melts, the ice A) absorbs energy from its environment. B) releases energy to its env

Mariulka [41]

Answer: Option (E) is the correct answer.

Explanation:

Latent heat is defined as the amount of heat required by per mole of a substance in order to change its state.

And, latent heat of freezing (fusion) is defined as the energy required for the phase change between a liquid and a solid without any change in their temperature.

Therefore, at zero degrees Celsius energy absorbed by the ice will be consumed in breaking the bond between the water molecules held together in the solid state.

Thus, we can conclude that when a block of ice at zero degrees Celsius melts, the ice absorbs energy but does not change its temperature.

3 0

3 years ago

A car traveling 75 km/h slows down at a constant 0.50 m/s2 just by "letting up on the gas." calculate (a) the distance the car c

Serjik [45]

Solution:

At 1st convert km/h to m/s. 1 km = 1000 m, 1 h = 3600 s, 1 km/m = 1000/3600 = 5/18 m/s

Initial velocity = 75 * 5/18 = 20.8 m/s

The car’s velocity decreases from 20.8 m/s to 0 m/s at the rate of 0.5 m/s each second. We have the final velocity, initial velocity, and the acceleration.

Now according to the equation determine the distance.

vf^2 = vi^2 + 2 * a * d

a = -0.5 m/s^2

0 = 20.8^2 + 2 * -0.5 * d

so d = 431.64 m

since we have the final velocity, initial velocity, and the acceleration. Use the following equation to determine time.

vf = vi + a * t

0 = 20.8 – 0.5 * t

Solve for t = 41 seconds

(c) the distance travels by it during the first and fifth second are.

d = vi * t + ½ * a * t^2

d1 = 20.8 * 1 – ½ * 0.5 * 1^2 = 20.55 m

The easiest way to the distance for the 5th second is:

d = vi * t + ½ * a * t^2, a = -0.5

d5 = 20.8 * 5 – ½ * 0.5 * 5^2 = 91.5 m

d6 = 20.8 * 6 – ½ * 0.5 * 6^2 = 106.8m

d6 – d5 = 15.3 m

this is the required solution.

3 0

3 years ago

Relativistic kinetic energy is conserved in all reference frames. True O False

Free_Kalibri [48]

Answer:

i think it is true

Explanation:

7 0

3 years ago

A ski resort consists of a few chairlifts and several interconnected downhill runs on the side of a mountain, with a lodge at th

Aleks04 [339]

A sketch of the junction between one chairlift and two runs is shown in the image attached below.
For this ski resort, it ultimately implies that the total number of lifts that are used in any closed loop would be equal to zero in accordance with Kirchhoff's loop rule.

<h3>What is Kirchhoff's loop rule?</h3>

Kirchhoff's loop rule is also referred to as Kirchhoff's second law or Kirchhoff's voltage law, and it states that the algebraic sum of all the electric potential differences around any closed loop is equal to zero.

<h3>How to connect two runs in series?</h3>

Since the chairlifts are analogous to batteries, and the runs are analogous to resistors, the two runs would represent resistors that are connected in series with the lift, which represents the battery. Similarly, these three runs can also be connected in parallel by altering the positions of the runs with the battery.

For this ski resort, it ultimately implies that the total number of lifts that are used in any closed loop would be equal to zero in accordance with Kirchhoff's loop rule.

Read more on Kirchhoff's loop rule here: brainly.com/question/15003023

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7 0

1 year ago

A gas is confined to a vertical cylinder by a piston of mass 2 kg and radius 1 cm. When 5J of heat are added, the piston rises b

Anarel [89]

The work done by gas is 0.753 J and change in internal energy is 4.247J

So we are given that mass is 2kg , radius 1 cm and the amount of heat is 5 cm

The piston raised by 2.4cm

As we know that Work done is PΔV

Where ΔV is change in volume

Therefore ΔV = πr^2 h = π x (.01)^2 x .024 =7.53×10^(-6)m^3

Here pressure is 10^5 pa

So W = $10^5\times7.53\times10^-(6)$

Therefore W = 0.753 J

Now coming to change in internal energy

Change in Internal Energy = Heat Added - Energy lost in work

∴ 5J - 0.753 J = 4.247J

Hence the change in internal energy is 4.247 J

Learn more about Work done here

brainly.com/question/16951089

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6 0

2 years ago