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MakcuM [25]
2 years ago
12

A dog goes for a walk in the neighborhood leaves home and take several displacements as follows. It first head

Physics
1 answer:
Korvikt [17]2 years ago
4 0

Answer:

sorry i couldn't answer your question I tried

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North America experienced all of the following during the last glacial period EXCEPT alpine glaciers covered the Rocky and Casca
Juli2301 [7.4K]

Answer:

the Hudson Bay was covered with alpine glaciers

Explanation:

During the last glacial period, large portions of North America were covered with ice. The majority of the ice was from the ice sheets that were covering Canada and the northern part of the United States, and the alpine glaciers on the mountain ranges. Hudson Bay was all frozen at this point of time. It was not covered with alpine glaciers though, instead it was covered with the ice of the extended ice sheets, with the ice cover reaching up to 2 km in thickness.

5 0
3 years ago
The seismic activity density of a region is the ratio of the number of earthquakes during a given time span to the land area aff
Natalija [7]

Answer:

0.0059

Explanation:

According to the question the seismic activity density is given by

\text{Seismic activity density}=\frac{\text{Number of Earthquakes over a given time span}}{\text{The land area affected}}

Here,

Number of Earthquakes over a given time span = 424

The land area affected = 71300 mi²

So,

\text{Seismic activity density}=\frac{424}{71300}\\\Rightarrow \text{Seismic activity density}=0.0059

The seismic activity density is 0.0059

8 0
2 years ago
Read 2 more answers
An experiment to measure the speed of light uses an apparatus similar to Fizeau's. The distance between the light source and the
Marina86 [1]

Answer:

2.88*10^{8} m/s

Explanation:

The speed of light is given by

c=\frac {2d}{t} and t=\frac {\theta}{\omega} hence

c=\omega\frac {2d}{\theta}

Speed of light is given by

c=900\times 2\pi(\frac {2\times 10}{\frac {2\pi}{2*800}}})=2.88*10^{8} m/s

4 0
3 years ago
Will mark brainliest.
egoroff_w [7]

Answer:

pls can you get a clearer image, then u can report back to me

6 0
2 years ago
Compute the voltage drop along a 26-m length of household no. 14 copper wire (used in 15-A circuits). The wire has diameter 1.62
zepelin [54]

Answer:

V= 2.7 [v]

Explanation:

The value of the resistance is given by:

R=L*\frac{Rho}{A}\\\\where:\\R=resistance\\L=Lenght\\Rho=Resistivity\\A=Transversal -Area

so:

R=26m*\frac{(1.68*10^{-8}ohm*m)}{\pi *(\frac{1.628*10^{-3}m}{2})^2}\\R=0.21 Ohm

We can calulate the voltage dropped using the Ohm's law:

V=I*R\\V=13A*0.21Ohm=2.7V

8 0
2 years ago
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