When electric current flows through the metal element of a light bulb, electrical current energy is converted to

When a planet is at its slowest orbital speed, its radius vector sweeps an area, A, in 45 days. What area will the radius vector

MArishka [77]

The area the radius vector will sweep is 0.889A

According to Kepler's second law, the radius vector sweeps out equal areas in equal times.

Let A = area and t = time period,

According to Kepler's law, A/t = constant

So, A₁/t₁ = A₂/t₂ where A₁ = area the radius vector sweeps at slowest orbital speed = A, t₁ = time period at slowest orbital speed = 45 days, A₂ = area the radius vector sweeps at fastest orbital speed, t₂ = time period at fastest orbital speed = 40 days.

Making A₂ subject of the formula, we have

A₂ = A₁t₂/t₁

Substituting the values of the variables into the equation, we have

A₂ = A₁t₂/t₁

A₂ = A × 40 days/45 days

A₂ = A × 40/45

A₂ = A × 8/9

A₂ = A × 0.889

A₂ = 0.889A

So, the area the radius vector will sweep is 0.889A

learn more about Kepler's second law here:

brainly.com/question/4639131

8 0

2 years ago

A uniform disk with mass m = 8.88 kg and radius R = 1.3 m lies in the x-y plane and centered at the origin. Three forces act in

Sophie [7]

Answer:

Part a)

$\tau_1 = 435.5 Nm$

Part b)

$\tau_2 = 0$

Part c)

$\tau_3 = 237.2 Nm$

Part d)

$\tau_x = 0$

Part e)

$\tau_y = 0$

Part f)

$\tau_z = 198.3 Nm$

Part g)

$\alpha = 26.4 rad/s^2$

Part h)

$KE = 5892.8 J$

Explanation:

Part a)

Torque due to F1 force is given as

$\tau = r \times F$

$\tau_1 = 1.3 \times 335$

$\tau_1 = 435.5 Nm$

Part b)

Torque due to F2 force is given as

$\tau = rF sin\theta$

$\tau_2 = 1.3(335)sin0$

$\tau_2 = 0$

Part c)

Torque due to F3 force is given as

$\tau = rFsin\theta$

$\tau_3 = 1.3(335)(sin33)$

$\tau_3 = 237.2 Nm$

Part d)

Net torque along x direction is given as

$\tau_x = 0$

Part e)

Net torque along y direction is given as

$\tau_y = 0$

Part f)

Net torque along x direction is given as

$\tau_z = 435.5 - 237.2$

$\tau_z = 198.3 Nm$

Part g)

angular acceleration is given as

$\tau = I \alpha$

$I = \frac{1}{2}mR^2$

$I = \frac{1}{2}(8.88)(1.3)^2$

$I = 7.5 kg m^2$

now we have

$198.3 = 7.5 \alpha$

$\alpha = 26.4 rad/s^2$

Part h)

angular speed of the disc after 1.5 s

$\omega = \alpha t$

$\omega = 26.4 \times 1.5$

$\omega = 39.6 rad/s$

now rotational kinetic energy is given as

$KE = \frac{1}{2}I\omega^2$

$KE = \frac{1}{2}(7.5)(39.6)^2$

$KE = 5892.8 J$

7 0

3 years ago

There is a girl pushing on a large stone sphere. The sphere has a mass of 8200 kgand a radius of 90 cm and floats with nearly ze

svetlana [45]

Answer:

35.1688 seconds

Explanation:

M = Mass of sphere = 8200 kg

R = Radius of sphere = 90 cm

F = Force = 30 N

Moment of inertia is given by

$I=\dfrac{2}{5}MR^2\\\Rightarrow I=\dfrac{2}{5}\times 8200\times 0.9^2\\\Rightarrow I=2656.8\ kgm^2$

Torque is given by

$\tau=I\alpha\\\Rightarrow FR=I\alpha\\\Rightarrow \alpha=\dfrac{FR}{I}\\\Rightarrow \alpha=\dfrac{30\times 0.9}{2656.8}\\\Rightarrow \alpha=0.01016\ rad/s^2$

For one rotation

$\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow 2\pi=0\times t+\dfrac{1}{2}\times 0.01016\times t^2\\\Rightarrow t=\sqrt{\dfrac{2\pi2}{0.01016}}\\\Rightarrow t=35.1688\ s$

The time taken to rotate the sphere from rest is 35.1688 seconds

3 0

3 years ago

Which statement is a description of Charles's law? The temperature and volume of a gas are directly proportional when pressure i

vfiekz [6]

Answer:

The temperature and volume of a gas are directly proportional when pressure is constant.

Explanation:

Charles's Law was proposed by a French chemist, Jacques Charles. The law states that "The volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant".

The law shows the relationship between volume and temperature at a constant temperature. It is mathematically expressed as:

V∝T(P,n constant)

7 0

4 years ago

If an airplane travels a distance of 500 km in 5 hours, what is its average speed?

zvonat [6]

The average is 100kmph

5 0

4 years ago