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finlep [7]
3 years ago
13

What is an Atwood Machine?

Physics
1 answer:
Lady_Fox [76]3 years ago
6 0
The best answer is letter (A) a double pulley system. Atwood Machine is normally used as a measurement in balancing to object to verify the mechanical law of motion with constant acceleration.
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Two planets A and B, where B has twice the mass of A, orbit the Sun in elliptical orbits. The semi-major axis of the elliptical
lozanna [386]

Answer:

2.83

Explanation:

Kepler's discovered that the square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit, that is called Kepler's third law of planet motion and can be expressed as:

T=\frac{2\pi a^{\frac{3}{2}}}{\sqrt{GM}} (1)

with T the orbital period, M the mass of the sun, G the Cavendish constant and a the semi major axis of the elliptical orbit of the planet. By (1) we can see that orbital period is independent of the mass of the planet and depends of the semi major axis, rearranging (1):

\frac{T}{a^{\frac{3}{2}}}=\frac{2\pi}{\sqrt{GM}}

\frac{T^{2}}{a^{3}}=(\frac{2\pi }{\sqrt{GM}})^2 (2)

Because in the right side of the equation (2) we have only constant quantities, that implies the ratio \frac{T^{2}}{a^{3}} is constant for all the planets orbiting the same sun, so we can said that:

\frac{T_{A}^{2}}{a_{A}^{3}}=\frac{T_{B}^{2}}{a_{B}^{3}}

\frac{T_{B}^{2}}{T_{A}^{2}}=\frac{a_{B}^{3}}{a_{A}^{3}}

\frac{T_{B}}{T_{A}}=\sqrt{\frac{a_{B}^{3}}{a_{A}^{3}}}=\sqrt{\frac{(2a_{A})^{3}}{a_{A}^{3}}}

\frac{T_{B}}{T_{A}}=\sqrt{\frac{2^3}{1}}=2.83

6 0
3 years ago
Read 2 more answers
I dolt understand what to do next please help
lidiya [134]
Divide 24 by 12.
24/t = 12
24/12 = t
24/12 = 2
t = 2
6 0
3 years ago
Name something that magnets has done for you in your life
kati45 [8]
Helped me learn how to spell words, held pictures or papers up, collected metal items that were lost
8 0
2 years ago
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What causes the pressure that allows diamonds to form in the mantle?
IceJOKER [234]
Diamonds are supposed to formed about 90 miles below the surface of the earth in the mantle. Therefore, the weight of the earth overhead them produces the pressure to form the diamond. The rocks weight overhead the mantle outcomes in high pressure and diamonds essential high temperatures and pressure to form as of carbon.Diamonds form in the mantle in definite precincts where situations are right for them to do so. There just chances to be the right critical temperature-pressure-mineral environment in the mantle in definite areas for their formation. 
6 0
3 years ago
The atomic number of a nucleus increases during which nuclear reactions
g100num [7]

Answer:

Answer A : Fusion followed by beta decay (electron emission)

Explanation:

Notice that you want the Atomic number to increase, that is the number of protons in a nucleus. So if all four cases given experience the same fusion of nuclei, the only one that net increases the number of protons in the last stage, is the reaction that undergoes a beta decay (with emission of an electron) thus leaving a positive imbalance of positive charge (proton generated in the beta decay of a neutron).

Therefore, answer A is the correct one.

3 0
3 years ago
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