All categories

3 years ago

Which of these models of the solar system first proved that the sun is at the center of the solar system?

Physics

2 answers:

soldi70 [24.7K]3 years ago

6 0

Answer:

Copernicus' heliocentric model

Explanation:

Nicolaus Copernicus was the first one to give the heliocentric model of the solar system. The heliocentric model of the solar system describes the sun to be at the center of the solar system and earth and other planets with their moons revolving about it in concentric orbits.

Kepler believed in Copernicus's heliocentric model but gave laws of planetary motion that described the orbit of the planets to be elliptical instead of circular.

Tycho Brahe view of the solar system was that sun revolved around earth but other planets revolved around the sun.

Ptolemy's geocentric model considered earth to be the center of the universe and sun and other planets revolving about it.

Anarel [89]3 years ago

4 0

I believe it was Copernicus' heliocentric model.

heliocentric - the sun is at the center and the planets revolve around it.

hope this helps :)

You might be interested in

collection of such objects we observe that they emit electromagnetic radiation of three different energies: 0.7 eV (infrared), 2

UkoKoshka [18]

It 45 because it has to be this and that and ur gay

4 0

3 years ago

The hottest climates on Earth are located near the Equator because this region

Ber [7]

You should select Choice-4 .

4 0

3 years ago

Why does wave height increase in shallow water??

Vitek1552 [10]

As the water russhes toward the shore, it rises because it is pushing against it.<span />

3 0

3 years ago

Consider a 20 cm thick granite wall with a thermal conductivity of 2.79 W/m·K. The temperature of the left surface is held const

kozerog [31]

Answer:

The right wall surface temperature and heat flux through the wall is 35.5°C and 202.3W/m²

Explanation:

Thickness of the wall is L= 20cm = 0.2m

Thermal conductivity of the wall is K = 2.79 W/m·K

Temperature at the left side surface is T₁ = 50°C

Temperature of the air is T = 22°C

Convection heat transfer coefficient is h = 15 W/m2·K

Heat conduction process through wall is equal to the heat convection process so

$Q_{conduction} = Q_{convection}$

Expression for the heat conduction process is

$Q_{conduction} = \frac{K(T_1 - T)}{L}$

Expression for the heat convection process is

$Q_{convection} = h(T_2 - T)$

Substitute the expressions of conduction and convection in equation above

$Q_{conduction} = Q_{convection}$

$\frac{K(T_1 - T_2)}{L} = h(T_2 - T)$

Substitute the values in above equation

$\frac{2.79(50- T_2)}{0.2} = 15(T_2 - 22)\\\\T_2 = 35.5^\circC$

Now heat flux through the wall can be calculated as

$q_{flux} = Q_{conduction} \\\\q_{flux} = \frac{K(T_1 - T_2)}{L}\\\\q_{flux} = \frac{2.79(50 - 35.5)}{0.2}\\\\q_{flux} = 202.3W/m^2$

Thus, the right wall surface temperature and heat flux through the wall is 35.5°C and 202.3W/m²

6 0

3 years ago

Starting from Newton’s law of universal gravitation, show how to find the speed of the moon in its orbit from the earth-moon dis

WARRIOR [948]

Answer: 1010.92 m/s

Explanation:

According to Newton's law of universal gravitation:

$F=G\frac{Mm}{r^{2}}$ (1)

Where:

$F$ is the gravitational force between Earth and Moon

$G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$ is the Gravitational Constant

$M=5.972(10)^{24} kg$ is the mass of the Earth

$m=7.349(10)^{22} kg$ is the mass of the Moon

$r=3.9(10)^{8} m$ is the distance between the Earth and Moon

Asuming the orbit of the Moon around the Earth is a circular orbit, the Earth exerts a centripetal force on the moon, which is equal to $F$ :

$F=m.a_{C}$ (2)

Where $a_{C}$ is the centripetal acceleration given by:

$a_{C}=\frac{V^{2}}{r}$ (3)

Being $V$ the orbital velocity of the moon

Making (1)=(2):

$m.a_{C}=G\frac{Mm}{r^{2}}$ (4)

Simplifying:

$a_{C}=G\frac{M}{r^{2}}$ (5)

Making (5)=(3):

$\frac{V^{2}}{r}=G\frac{M}{r^{2}}$ (6)

Finding $V$ :

$V=\sqrt{\frac{GM}{r}}$ (7)

$V=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24} kg)}{3.9(10)^{8} m}}$ (8)

Finally:

$V=1010.92 m/s$

5 0

3 years ago