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snow_tiger [21]
3 years ago
9

Which inventor created a delivery system for electricity that was deemed safer than Thomas Edison's system?

Physics
2 answers:
vodomira [7]3 years ago
5 0
c. George Westinghouse is the inventor who created a delivery system for electricity that was deemed safer than Thomas Edison's system.
SVETLANKA909090 [29]3 years ago
4 0
<h3><u>Answer;</u></h3>

C. George Westinghouse

<h3><u>Explanation;</u></h3>
  • <em><u>George Westinghouse was an inventor who is significant in promoting the use of electricity for power and transportation. He created the first large system to supply electricity for multiple uses.</u></em>
  • <em><u>He formed the Westinghouse electric and manufacturing company in 1884. He created delivery system for electricity that was deemed safer than that of Thomas Edison. </u></em>
  • He also developed a transformer that could bring alternating current electricity down form high voltage to low and hence making it possible to transmit it for long distances while making it ready for use.
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A sound is recorded at 19 decibels. What is the intensity of the sound?
sp2606 [1]

1 \times 10^{-10.1} \mathrm{Wm}^{-2} is the intensity of the sound.

Answer: Option B

<u>Explanation:</u>

The range of sound intensity that people can recognize is so large (including 13 magnitude levels). The intensity of the weakest audible noise is called the hearing threshold. (intensity about 1 \times 10^{-12} \mathrm{Wm}^{-2}). Because it is difficult to imagine numbers in such a large range, it is advisable to use a scale from 0 to 100.

This is the goal of the decibel scale (dB).  Because logarithm has the property of recording a large number and returning a small number, the dB scale is based on a logarithmic scale. The scale is defined so that the hearing threshold has intensity level of sound as 0.

                     \text { Intensity }(d B)=(10 d B) \times \log _{10}\left(\frac{I}{I_{0}}\right)

Where,

I = Intensity of the sound produced

I_{0} = Standard Intensity of sound of 60 decibels = 1 \times 10^{-12} \mathrm{Wm}^{-2}

So for 19 decibels, determine I as follows,

                   19 d B=(10 d B) \times \log _{10}\left(\frac{I}{1 \times 10^{-12} W m^{-2}}\right)

                  \log _{10}\left(\frac{1}{1 \times 10^{-12} \mathrm{Wm}^{-2}}\right)=\frac{19}{10}

                  \log _{10}\left(\frac{1}{1 \times 10^{-12} \mathrm{Wm}^{-2}}\right)=1.9

When log goes to other side, express in 10 to the power of that side value,

                  \left(\frac{I}{1 \times 10^{-12} W m^{-2}}\right)=10^{1.9}

                  I=1 \times 10^{-12} \mathrm{Wm}^{-2} \times 10^{1.9}=1 \times 10^{-12-1.9}=1 \times 10^{-10.1} \mathrm{Wm}^{-2}

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a truck drives up a hill with a 15 incline. if the truck has a constant speed of 22m/s, what are the horizontal and vertical com
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Answer:

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Vertical component (Fv) = ?

Harizontal component (Fh) =?

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