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Cloud [144]
3 years ago
11

PLZ HELP on THIS QUESTION

Mathematics
1 answer:
Greeley [361]3 years ago
8 0
Its a rectangle cut the corners
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5. A history lecture hall class has 15 students. There is a 15% absentee rate per class meeting.
Tasya [4]

Answer:

I think the answer is A

Sorry if i am wrong

Step-by-step explanation:

5 0
3 years ago
If X=5 and 5=y, then x=y <br> Ar algebraic equality property justifies the above statement?
RUDIKE [14]

Answer:

Yes.

Step-by-step explanation:

According to the Transitive property of the Algebraic properties of equality, two values are said to be equal is they are differently equal to a corresponding third party. This is, If a=b and b=c then a=c.

Hence, if x=5 and 5=y, then following the transitive property of Algebraic properties of equality, x=y, hence the Algebraic property of equality Justifies the statement.

3 0
3 years ago
Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1
weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})

This gives

f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})

Evaluate the products

f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})

Evaluate the like terms

f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}

So, we have

f(x) = x²+ 2/3x - 1/9

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

7 0
1 year ago
The app isn't letting me post the picture alone so this is just here so I can post the picture ;-;​
labwork [276]

Answer:

  (x, y) = (0, -2248)

Step-by-step explanation:

<u>Substitution</u>

Substitute for y:

  300x -2248 = 350x -2248

  0 = 50x . . . . . . . . add 2248-300x to both sides

  x = 0

  y = 300·0 -2248

The solution is (x, y) = (0, -2248).

__

<u>Elimination</u>

Subtract the first equation from the second.

  (y) -(y) = (350x -2248) -(300x -2248)

  0 = 50x

  x = 0

  y = 300·0 -2248

The solution is (x, y) = (0, -2248).

__

<em>Additional comment</em>

If you think for a bit about what the graph looks like, you realize both lines cross at their y-intercept, (0, -2248). That point of intersection is the solution to the system of equations.

7 0
2 years ago
What is the multiplicative rate of change for the exponential function graphed to the left​
kifflom [539]

Looking at the given points on the right side from (0,2) to (1,6) for 1 increase in X ( 1-0=1) the Y value increases by 3 ( 6/2 = 3)

This same increase happens for th other two points: 18/6 = 3

54 / 18 = 3

The rate of increase is 3.

6 0
2 years ago
Read 2 more answers
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