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Dafna11 [192]
3 years ago
10

Triangle ABC is similar to triangle DEF . The length of AC¯¯¯¯¯ is 12 cm. The length of BC¯¯¯¯¯ is 18 cm. The length of DF¯¯¯¯¯

is 10 cm.
What is the length of EF¯¯¯¯¯?



Enter your answer in the box.
Mathematics
2 answers:
Assoli18 [71]3 years ago
6 0

The person below/above (i think it's below) is correct, EF = 15

don't rate/vote me, vote/rate her.  I'm just confirming that they are correct

Have a good day

krok68 [10]3 years ago
5 0
If you make a proportion,
12 18
--- = ---
10 x
when you cross multiply
12x=180
x=15
EF= 15
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Answer:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

df=n-1=44-1=43  

p_v =P(t_{(43)}>1.436)=0.079  

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

Step-by-step explanation:

Information given

\bar X=13.88 represent the sample mean

s=3.14 represent the sample standard deviation

n=44 sample size  

\mu_o =13.2 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis to test

We want to conduct a hypothesis in order to check if the true mean has increased from 2008 , and the system of hypothesi are:  

Null hypothesis:\mu \leq 13.2  

Alternative hypothesis:\mu > 13.2  

The statistic for this case is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculating the statistic

Replacing the info given we got:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

P-value

The degrees of freedom are:

df=n-1=44-1=43  

Since is a right tailed test the p value is:  

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Decision

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