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Georgia [21]
3 years ago
7

What was the names of Jupiter’s big pet dog?

Mathematics
1 answer:
Rama09 [41]3 years ago
8 0

IDK sorry bout that bud

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The maximum afternoon temperature in Granderson is modeled by t=60-30 cos (x<img src="https://tex.z-dn.net/?f=%20%5Cpi%20" id="T
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The equation is t=60-30 cos (x \frac{\pi}{6})

the -30 expression, is subtracting, if negative, from the 60
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and then the 30 expression will ADD to the 60 amount
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when does that happen, when cosine is negative and at its highest,
well, cosine range is -1\le cos(\theta ) \le 1
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so...  let's find a value that makes that expression to cos(\pi)

\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=6&#10;\\\\&#10;thus&#10;\\\\&#10;t=60-30 cos (6 \frac{\pi}{6})\implies t=60-30 cos (\pi )&#10;\\\\&#10;t=60-30[-1]\implies t=60+30\implies t=90

----------------------------------------------------------------------------------------
so...for August, that'll mean


\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=7&#10;\\\\&#10;t=60-30 cos (\frac{7\pi}{6})\implies t=60-30\left( -\cfrac{\sqrt{3}}{2} \right)&#10;\\\\&#10;t=60+(15\cdot \sqrt{3})\implies t\approx85.98^o


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Your answer would be 
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Answer:

See explanation and image attached

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32/36 simplified is 8/9 
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